這題，下面的解答看不懂

2-39 1,3-Cyclobutadiene is a rectangular molecule with two shorter double bonds and two longer single bonds. Why do the following structures not represent resonance forms? 一 2.39 The two structures are not resonance forms because the positions of the carbon atoms are different in the two forms.

請問有人看得懂嗎😂

Genetics 普通生物學 UNIT THREE 觀念11: DNA定序(DNA Sequencing) 端 單股DNA和帶有放射性 1. Sanger法(Sanger method)或Sanger雙去氧鏈終止法(Sanger dideoxy chain termination method) : 1. 以5碳糖上第2和第3個碳均去氧的核苷酸為材料,合成的DNA之3', 不能再接新的核苷酸,造成DNA终止。 2. dsDNA加熱變性,快速冷卻成單股DNA, (PP)標示的primer 配對。 3. 反應時分成四管: a) #AZDNA+primer+DNA polymerase+4dNTPs+ddATP b) ADNA+primer+DNA polymerase+4dNTPs+ddTTP c) ADNA+primer+DNA polymerase+4dNTPs+ddGTP d) 單股DNA+primer+DNA polymerase+4dNTPs+ddCTP 4. 終止反應,並用聚丙醯凝膠(polyacrylamide gel) 電泳分離。 5. 顯影後判讀X光片即可讀出DNA序列。 6. Frederick Sanger 因為這個方法獲得1980年諾貝爾獎。 Primer 5 OH 3 3' -CTAAGCTCGACT Template dCTP, dGTP, DATP, DTTP + ddATP - GATTCGAGCTGddA GATTCGddA F GddA + ddCTP GATTCGAGddC GATTddC + ddGTP - GATTCGAGCTddG GATTCGAddG GATTCddG ddG + ddTTP - GATTCGAGCddT -GATddT - GAddT G 3' 12 11 10 G C uuu9876543 21 5 As Tcc AccTT AG Autoradiogram of electrophoresis gel Sequence of complementary strand 500 1610 T天就在 下一秒就看到,

希望好心人提供答案🙏🙏

4.( )篮球團隊基本防守,擔任第一線防守者要上前壓迫持球者,盡力阻擋其執行傳球、切入與投籃, 若遭突破要積極跟隨,以配合二線防守球員之關門防守迫使持球者停止運球。P.56 5. ( )籃球比賽規則,進攻隊伍進攻時間若因防守方單方面的犯規或違例後,若無罰球,且進攻時間 少於二十四秒,則進攻時間應重設為二十四秒。P.63 6.( )籃球大三元紀錄(Triple-Double),是指球員在單場比賽中,五大重要紀錄有三項能夠達到十次 以上,而大部分的大三元記錄通常是依靠得分、阻攻與籃板球等三項所創造。 7.( )籃球規則一開始是沒有進攻時間限制的,之後為了加快節奏、增加比賽可看性,因此規則不斷 研修,演變為目前進攻時間三十秒的規則。P. 63 8. ( 13 秒違例規則指的是,進攻時不論有沒有持球都不可以在禁區中待超過3秒的時間。P. 63 選擇題 1.( )籃球防守有兩大類型,可區分為人盯人防守與下列何者?(A)人盯球防守 (B)壓迫性防守 (C) 趨前防守 (D)區域防守。P.55 2. ( )籃球進行防守時,為避免迎上前防守時失去重心而被持球者突破,能有效保持重心的技巧步伐 是? (A)以小碎步趨前(B)以滑步靠近(C)以交叉步前進(D)以螃蟹步移動。P.55 3. ( )籃球進行防守滑步,以下動作要領之敘述,何者有誤?(A)高舉的雙手 (B)前後移動 (C) 重心不可高低起伏(D) 雙腳不可交叉。P.56 4. ( )籃球執行防守動作,何者的防守視線需同時看到持球者與所負責位置之無持球者?(A) 第一 線防守球員(B)第二線防守球員 (C)第三線防守球員 (D)後備球員。P.58 5. ( )籃球執行防守動作,何者所站位置應涵蓋場上所有攻防動態,以即時補防籃下以及遠邊空手球 員,並隨時發出聲音提供隊友場上相關資訊?(A)第一線防守球員(B) 第二線防守球員 (C) 第三線防守球員 (D)第四線防守球員。P.58 6. ( )以下對於籃球個人防守動作要領之敘述,何者有誤?(A)雙腳張開寬於肩膀,腳尖微微抬起 (B)膝蓋彎曲,身體挺起,像坐下般將整體重心壓低,保持機動性(C)雙手置於身體前方, 手隨球移動干擾持球 (D)雙手置於身體前方,一手張開阻斷傳球路線。P.55 7. ( )籃球以滑步執行防守時,重心應如何維持? (A)忽高忽低以擾亂對手 (B)維持高重心以壓迫 對手 (C)忽前忽後以破壞對手節奏 (D)保持平衡,不高低起伏。P.56 8.( )籃球團隊基本防守,當第一線防守遭運球突破時應積極跟隨,與二線幫忙協助防守,稱為? (A) 交換防守 (B)區域聯防 (C)關門防守 (D)誘敵防守。P.56 9.( )籃球團隊基本防守,第二線防守球員的視線應在?(A)持球者(B)所負責位置之無持球者(C) 持球者與所負責位置之無持球者(D)涵蓋場上所有攻防動態。P.58 10. ( )籃球運動的五大重要紀錄, 大部分的大三元記錄通常是依靠哪三項所創造? (A)得分、助攻 與抄截 (B)得分、籃板球與阻攻 (C)籃板球、抄截與助攻(D)得分、助攻與籃板球。 11. ( )在籃球比賽中球員獲得阻攻紀錄是指? (A)成功阻擋或破壞對方球員間的傳球(B)在未犯 規下,成功阻擋對方控球球員往籃框靠近 (C)成功攔截拿下對方球員間的傳球 (D)當對手 進攻球員投籃後,防守球員成功將球於半空中拍打落地。 12. ( )籃球規則進攻時間限制,防守方單方面的犯規或違例後,若無罰球,且進攻時間少於秒,則 進攻時間須重設? (A)5 秒(B)8秒(C)14 秒(D)20秒。P.63 9 9 13. ( )籃球規則一開始是沒有進攻時間限制的,之後為了加快節奏、增加比賽可看性,因此規則不 斷研修,演變為目前多少進攻時間的規則? (A)十八秒(B)二十四秒(C)三十秒(D)三 十六秒。P.63 14.( )籃球規則,無持球者不可在禁區超過多少時間?(A)3 秒(B)5 秒(C)8 秒(D)12 秒。P.63 15.( )籃球規則,進攻隊伍必須幾秒內將球過半場? (A)3 秒(B)5 秒(C)8 秒(D)24 秒。 P.63 16. ( )第一線防守球員應該努力做到哪一件事?(A)及時關門協防 (B)抄截 (C)積極壓迫干擾持 球者(D)阻攻。P. 56 17. ( )防守最重要的目的是?(A)拖延比賽時間 (B)取得球權(C)抄截 (D)阻攻。P. 54

求證明(b)的過程😭感謝~

(I) A soccer player kicks a ball at 15 m/s at 20° above the horizontal to another member of the team. At what speed should the second player run in order to reach the ball just as it lands? The initial separation of the players is 25 m. he (II) A basketball player throws the ball with initial velocity vo at above the horizontal to the hoop which is located a horizontal distance L and at a height h above the point of release, as shown in Fig. 4.44. (a) Show that the initial the speed required is given by an vſ gL 2 cosO(tan 9 - h/L) (b) Show that the angle a to the horizontal at which it reaches the hoop is given by tan a = 2h/L - tan 0. = Vo h L FIGURE 4.44 Problem 16

想請問E是錯在哪裡？ 中節是只發生於mitotic phase（DNA濃縮且複製完畢時）嗎？還是當DNA在S phase 複製時就有了？ 如果是發生於mitotic phase ，又此時期很短，所以一般我們看到的都是細胞處於interphase

D 5) Suppose a biologist can separate one of a dozen pieces of chromatin from a eukaryotic (animal) nucleus. It might consist of which of the following? woon A) one-twelfth of the genes of the organism B) two chromosomes, each with six chromatids C) a single circular piece of DNA LD) two long strands of DNA plus proteins erns that we tot protein E) two chromatids attached together at a centromere 付 也

求解答案是否正確

Multiple-choice questions: (70 points) write the letter of statement that is not true: 1. A.B.U The Drude Model: (a) It is a classical approach using concepts from the kinetic theory of gases. (b) A relaxation-time approximation is used where the probability of collision is l/t. (c) No forces act on the electrons in between collisions. (d) It predicts accurately the electronic heat capacity of metals. 2. The Sommerfeld Model: (a) The crystal potential is replaced by an average Coulomb potential. (b) The separation of states is so close that a continuum model can be applied. (c) The electrons are highly localized due to a strong crystal potential. (Q) The energy of the highest occupied state at 0 K is the Fermi energy. 3. Density of states in k-space, N(k): (a) N(k) is determined by the boundary value conditions. (b) For lattices in any dimensions, N(k) is constant in k-space. (C) N(k) depends on the direction and magnitude of k. (d) It is directly proportional to the volume of the crystal. E影響, c 4. The Fermi surface of a metal: (a) is responsible for many of the transport properties of the metal, (b) depends on the nature of the chemical bonds, (c) is always a sphere, (d) can involve mixing of electron orbitals. ✓ 5. The conductivity of a material () increases with the mobility of its carriers, (b) increases with the density of carriers, (C) it is inversely proportional to the energy gap. cogu changes with temperature. 6. BID Plasmons: (a) They are an important characteristic of the Sommerfeld electron gas model. (b) Plasmons occur spontaneously in metals. (c) They are related to charge density oscillations. (d) The Plasmon energy is typically of the order of 10 eV. The Fermi energy Ef in intrinsic semiconductors 8) is usually close to y E, at OK (b) it ACiD. can increase or decrease with temperature depending on the ratio of hole and electron effective masses, (c) it represents the point at which the probability of occupation is 12, even though there may not been any states with that energy, (d) its value relative to the electronic bands must remain unaffected in the presence of defects or interfaces.

微積分的問題，雙倍三倍的概念

27-30 MODELING, APPLICATIONS 27. Exponential growth. If the growth rate of a culture of bacteria is proportional to the number of bacteria present and after 1 day is 1.25 times the original number, within what interval of time will the number of bacteria (a) double, (b) triple?

求詳解，感恩

1 2. 3 4. D) Basically, they go on voyage after voyage in search of an immense treasure buried somewhere by the King of the Pirates, Gol D. Roger. B C 閱讀測驗1 There he flies, turns, lands and—to da- a disaster is saved, by Superman. “Come on,” you roll your eyes. “That's NOT real.” But admit it -we LOVE superman. Since the debut of the prototypical superhero Superman in 1938, stories of various superheroes have dominated American comic books and crossed over into such other media as films and animations. Versatile as these super characters may be, they do share certain traits. We know the double-life secret that Peter Parker is Spider-man, Bruce Wayne the Batman, and Clark Kent the Man of Steel. The secret identity has a civilian job while the “super-me” puts on an eye-catching costume, or custom-made accessories like Wonder Woman's bracelets. We are concerned that the bad guys play tricks so as to hurt these protectors. Fortunately enough, our superheroes normally have a base to go for “restoration” to. The Batcave has everything the Batman needs. Isn't that great? Furthermore, these super icons may have some backups and do not always have to work independently. The Fantastic Four or X-men team up as they have common origins or sponsors. These super teams are like a marvelous circle. Nevertheless, there are downsides being a superhero. Credits are not always given as the Batman and Spider-man meet with public skepticism or outright hostility. A superhero may even lose control as the Hulk has an issue with his violent alter ego. We love to see the superheroes think big and achieve big. They for sure reflect what we are and what we want to be. In summary, superheroes are popular and iconic because they each represent a large part of a society's traits and values. Everyone can relate to at least one hero and villain, because those heroes are designed to show the best parts of society, and the villains represent the worst parts. 5 What can we say about the author's tone? (A) Angry. (B) Formal. (C) Harsh. (D) Relaxed. 48 主题5 藝文世界

作業寫不出來😭微積分

if (x, y) = (0,0) ( 20 points ) Let f(x, y) = x²y² x4 + y + 0, if (x,y) = (0,0) (a) Does lim f(x,y) exist ? Give reasons. (x,y) → (0,0) (b ) Find the partial derivatives fx(0,0) and fy(0,0).

請問有人知道這三題的算法跟答案嗎(´･ω･`)

線上盛一遊戲橘子 < > a physexp.thu.edu.tw/~APNC/NP/ 07 古 課程平台練習 科技與物理公告 講義 測驗成績 FB 連結至基礎應用數學 1.古典力學 NP-003 login P01 P02 P03 P04 POS P06 P07 P08 得分與答題次數 2.圓週運動與 文學 3.熱力學 Problem7(填充題) Three moles of helium are initially at 20 °C and a pressure of 1 atm(=1.01 x 10 Pa). (a)Calculate the initial volumne of the helium gas. What is the work done by the gas if the volume is doubled (b) at constant pressure, or (c) isothermally? 提示:可將氮氣視為理想氣體,等溫過程所做的功的公式為:W=nRT Ind)。 (03小題) 一熱力學定律(25) 「溫度(9) 下與美容量(24) ANP-L05 理想氣體與功(2 氣體運動論文 ANP-L06 ONP-003 4章皇 (a)the initial volume= 分數=2 可嘗試次數= 5 m3 m 相對誤差=0.05 目前剩餘 5次,可繼續嘗試 :30 5.學 6.波動與光 近代物理 更新剩餘次数 B. 近代科技1 9近代科技 機器學習 (b)work done at constant pressure , W= 分數= 2 可嘗試次數=5 相對誤差-0.05 ] 目前剩餘 5次,可繼續嘗試 10.近代科技 量子電腦 :31 VPYTHON https:/physexp thu edu tw/LAP 8/NP-Q03-T-07 php 重設