M=>, < 13
切線
切果了
8. 若圓C:x+y²-12x+ay+b=0切直線L:3x-4y+3 = 0 於點 P (3,c),求序組(a,b,c)=
〔搭配單元7〕
d(0; 2)
118+2a+31
√ q + 16
|2||201
(x² 124 +36) + [ytay 1² ) = - +36 + 1/4
(x-6)² + (y+) ²
= -6+3 6+1²/12/²
P(3,6) L=3X-4x+3° 1
P L=3X-47+3=0 $cl
2
9+46+3=0
12+40=0
O
4C =12
(= -3
0(6, 1)
Y =
√-b²+36 + 1 = ²
20
r = op
9+6=9
2
= 15
121+29/
√9+6=0
30-5a
2
444 84 at 4a² 225 +
216 +849 +49² = 30-52
2
432 +84a +4a² = 30-5α
49²³² +899 +40) =6
134 201
13
3
67
3/4
25
Y
q
45