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4. The cross-linking reaction of polyvinyl alcohol forms four water molecules for every B(OH)4 that cross- links two polymer chains. Given the sections of polyvinyl alcohol chains below, sketch how B(OH)4 cross-links the chains. Through what atom chain linkages are the C-C polymer backbones connected? CH CH₂ H O-H O-H H H CH₂ H-O. +B (OH)4 H H CH₂

為什麼[A(org)]=n[An(org)]成立 (第三張圖equation 7.9) 感謝

Experiment 7 Experiment 7 The partition of Organic acid between Water and Organic solvent Objectives Understand the partition of a solute between two immiscible solvents. Introduction A chemical analysis that is performed primarily with the aid of volumetric glassware (e.g., pipets, burets, volumetric flasks) is called a volumetric analysis. For a volumetric analysis procedure, a known quantity or a carefully measured amount of one substance reacts with a to-be-determined amount of another substance with the reaction occurring in aqueous solution. The volumes of all solutions are carefully measured with volumetric glassware. The known amount of the substance for an analysis is generally measured and available in two ways: 1. As a primary standard: An accurate mass (and thus, moles) of a solid substance is measured on a balance, dissolved in water, and then reacted with the substance being analyzed. 2. As a standard solution: A measured number of moles of substance is present in a measured volume of solution - a solution of known concentration, generally expressed as the molar concentration (or molarity) of the substance. A measured volume of the standard solution then reacts with the substance being analyzed. The reaction of the known substance with the substance to be analyzed, occurring in aqueous solution, is generally conducted by a titration procedure. The titration procedure required a buret to dispense a liquid, called the titrant, into a flask containing the analyte. A reaction is complete when stoichiometric amounts of the reacting substances are combined. In a titration this is the stoichiometric point. In this experiment the stoichiometric point for the acid-base titration is detected using a phenolphthalein indicator. Phenolphthalein is colorless in an acidic solution but pink in a basic solution. The point in the titration at which the phenolphthalein changes color is called the endpoint of the indicator. Indicators are selected so that the stoichiometric point in the titration coincides (at approximately the same pH) with the endpoint of the indicator.

想請問這兩題微積分怎麼解🙏🙏

113年度作業一 隱函數 1. Find the tangent line of the curve (Implicit Differentiation) sin(xy2) + x²+x+1 = 2y2 at y" (2,-1.99883) 2. Given f(x) = = d (Hint: In(u) = dx x² (1-x)³ sec-1(1+x) 1 du u dx , d dx , find f" (2). sec-1 (u) 1 du = |u|√u²-1 dx , |u|> 1 )

看不懂老師的算式 有人能幫我拆解步驟解釋一下嗎 或是另外寫易懂的算式過程 拜偷

A sample containing 25.14g of neutral salts, glucose and a sodium carbonate/bicarbonate buffer was dissolved in 100 ml of water. A 25 ml aliquot of the resultant solution required 20.35 ml of 0.0987 M HCl when titrated to the PP end-point. A second 25 ml aliquot was titrated to the MO end-point and required 56.75 ml of the acid. Calculate the percentage of Na2CO3 (molecular weight 106) and NaHCO3 (molecular weight 84) in the sample. 含有25.14克中性鹽、葡萄糖和碳酸鈉/碳酸氫鈉的樣品將緩衝液溶解在100ml水中。需要25毫升等份所得溶液滴定至PP終點 時,使用20.35ml 0.0987 M HCl。第二份25毫升等分樣本是滴定至MO終點,需要56.75ml酸。計算百分比樣品中的Na2C03 (分子量106)和NaHCO3(分子量84) 39

想請問這題的醚和胺的沸點可以如何排序？ 因為我印象中氫鍵的影響比極性大，因此不了解為什麼胺的沸點比醚小 謝謝🙏

56. List the following compounds from highest boiling to lowest boiling: NH₂ 分子量 - * b₁p= HB dipole 為何 ↓ relatively weak HB OH ⑥ dipole-dipole interactions Q= LOH has two groups that hydrop bund ~HNY WH HB的影響力不是通常大於極性嗎? OH Obme electronegative thun N, OH Ingen bond are stomper than NH₂ primary amines form stronger hydrogen bond than seculary relatively weak no bydrogen had hydrogen bonds HB→分子量(分散戶 nly dipic dipole →接觸面積→極性 hah no hydrogen bon weaker dipole-dipole interactions tha oxygen-containing compounds because N is low electro negative than O

這題的解答給的是C, 該怎麼求出，感謝！

6. Find the volume of the solid whose region is the intersection of the cube {(x, y, z) : |x| ≤ 1, |y| ≤ 1, || ≤ 1} and the ball {(x, y, z) = x² + y²+ z² < 2}. 16 (A) 32(√2-1). (B) (8-√2). 3 16 (C) (10- √2)TT. (D) √√2π. 3 32 3

哪一個段落沒有主題句？ 我覺得是第一個，對嗎？ 要怎麼替這個段落寫出主題句呢？

2 Despite different home cultures and countries, international students' main overall motivation is the desire get out on their own, to carve out a new direction in their lives. "Foreign students" do not casually abandon the comforts of family and cultural ties; they have done their homework on Canadian schools. All their preparation, though, cannot prepare them for the loneliness and ongoing difficul- ties they face, from cold winters to financial issues related to the higher tuition fees they must pay. Some students, though, emigrate to escape those same tight- knit families and bonds that others find so painful to leave behind. A Macleans "On Campus" report notes that family expectations may be opposed to students' visions for themselves and lead them to reject accepted values and career paths in their hometowns and countries. Csilla, a web-design student at Waterloo admits, "I was always supposed to enter my family's restaurant business in Budapest, but I felt suf- focated even working part-time as a server. Web design is my passion, and I wanted 12: CAUSE OR EFFECT [- a completely fresh start, something that is completely my own ("International Stu- dents"). Finding independent paths to their own dreams is the key here, whether students choose those paths as a result of personal ideals or as a reaction to pre-set future plans.

答案都是8.79

9.21 A wheel of diameter 20.0 cm starts from rest and rotates with a constant angular acceleration of 3.50 rad/s². Compute the radial acceleration of a point on the rim for the instant the wheel completes its second revolution from the relationship (a) arad w'r and (b) arad = v²/r. =

自動控制 求解

Design a compensator such that the damping ratio < = 0.5 and the undamped natural frequency Wn 2 rad/sec. R(s) + G.(s) Compensator (a) Dominant closed-loop poles? (b) Angle deficiency? (show the diagram) (c) Lead or lag compensator? 1 0.1s+1 1 52 G(s) → C(s)

綠色螢光筆的不是很了解 1. 為什麼會有5呢？ 2. 為何要加52000

dand 2. (LO 3, 4) On January 1, 2020, Hayslett AG had the following equity accounts. Share Capital-Ordinary (€10 par value, 260,000 shares issued and outstanding) Share Premium-Ordinary Retained Earnings During the year, the following transactions occurred. April 1 May 1 June 1 Aug. 1 31 Dec. 1 Declared a €1.50 cash dividend per share to shareholders of record on April 15, payable May 1. Paid the dividend declared in April. Announced a 2-for-1 share split. Prior to the split, the market price per share was €24. Declared a 10% share dividend to shareholders of record on August 15, distributable August 31. On August 1, the market price of the shares was €10 per share. Issued the shares for the share dividend. Declared a €1.50 per share dividend to shareholders of record on December 15, payable January 5, 2021. Determined that net income for the year was €600,000. 31 Instructions Solution 2. a. Apr. 1 May 1 June 1 Aug. 1 31 Dec. 1 31 1 Cash Dividends (260,000 × €1.50) Dividends Payable Dividends Payable Cash No journal entry needed for share split Share Dividends (52,000* × €10) Ordinary Share Dividends Distributable (52,000 × €5) Share Premium-Ordinary (52,000 × €5) *520,000 x.10 Ordinary Share Dividends Distributable Share Capital-Ordinary Cash Dividends (572,000** × €1.50) Dividends Payable **(260,000 × 2) + 52,000 Income Summary €2,600,000 1,500,000 3,200,000 Retained Earnings Retained Earnings Share Dividends Cash Dividends (€390,000+ €858,000) 390,000 390,000 520,000 | 260,000 858,000 600,000 1,768,000 390,000 390,000 260,000 260,000 Prepare dividend ent section. 260,000 858,000 600,000 520,000 1.248,000 14. Luz (a) r equ 15. pre 16- 17 for 18