第五題是因為沒除2被扣分嗎

X = 109. (Y+ JY²41) =>2²=Y+SY²³1 5²(x) = 2^²=√²+1 4. (10%) 證明 f(x)=log2 (2+VⅠ? + 1) 為奇函數,並求其反函數 5. (10%)寫出三角函數積化和差(三條) 公式。 (1) sin (α(+B) + sin(2-³)=2 sinx cUSB (05(x-B)-(056d+ ° (2) (05 (α-B) + CO₂(X+B) =Zcosx.cosB³ = 2 sind sing (3) 6. (10%) 將 sin(cos a + tan-y) 化簡為 工, y 的(不含三角函數之)表示式,其中 -1 ≤x≤1, y ∈ P (b) (5%) sin(tan-¹x) (c) (5%) sin (2 tan-¹ x) (d) (5%) sin(cos-¹2) 1 7. (10%) 證明 2 tan' X 6. sin (d+B) = sind cosB+ cosa sin B ()() + (x)( 2x X41 = COS x²-1 tt x2+10 面 Jity AUF-X² Thoxe Storipy THIN x -10

想問E1.7第三題為什麼是資產減少

ze the effect of transactions on liabilities, and equity. Instructions List the numbers of the above transactions and describe the effect Ul ties, and equity. For example, the first answer is: (1) Increase in assets and increa E1.7 (LO 4) Collins Computer Timeshare entered into the following transactions during May 2025. Cu XH 1. Purchased computers for R$20,000 from Digital Equipment on account. 2. Paid R$4,000 cash for May rent on storage space. 3. Received R$17,000 cash from customers for contracts billed in April.. 4. Performed computer services for Viking Construction for R$4,000 cash. 5. Paid Tri-State Power R$11,000 cash for energy usage in May. 6. Shareholders invested an additional R$29,000 in the business in exchange for ordinary shares. B 7. Paid Digital Equipment for the computers purchased in (1) above. Fran 8. Incurred advertising expense for May of R$1,200 on account. polque 100 avly of brothe ow na')) Instructions Indicate with the appropriate letter whether each of the transactions above results in: a. An increase in assets and a decrease in assets. b. An increase in assets and an increase in equity. c. An increase in assets and an increase in liabilities. d. A decrease in assets and a decrease in truequity. e. A decrease in assets and a decrease in liabilities. f. An increase in liabilities and a decrease in equity. g. An increase in equity and a decrease in liabilities.

請問第11題怎麼算

In Exercises 5 through 18, sketch the given region RAS and then find its area. 5. R is the region bounded by the lines y = x, y = -x, and x = 1. 6. R is the region bounded by the curves y = x², y = -x², and the line x = 1. 7. R is the region bounded by the x axis and the -x² + 4x - 3. curve y = 8. R is the region bounded by the curves y = e, .ar y = ex, and the line x = In 2. 9. R is the region bounded by the curve y = x² - 2x and the x axis. [Hint: Note that the region is below the x axis.] .85 10. R is the region bounded by the curve y the lines y = x and y = = X 8 1 11 and 11. R is the region bounded by the curves y = x² - 2x and y -x² -x² + 4.

第二小題、第3小題求過程🥺 答案：-42、2

3₁ % f(1) = -2₁ f^(1)=3, 9(₁) = 2; g'(1) = -1 731) Jak # 求下列問題 + x ( faj 9(x)} | X= = dx (2) / (f² (4x-3) +(3ײ-5)) |x-1 32 +₂ ( f (57) + = (2-1)) |x-1= in d

離散數學 第一章 請問第19題怎麼算 第二張是答案可以參考

19. How many times is the print statement executed for the following program segment? (Here, i, j, k, and m are integer variables.) ni diaq orta ) for i:=1 to 20 do as U = for j := 1 to i do for k := 1 to j do for m:= 1 to k do groll print (i* j) + (k * m)

請問第13題的b怎麼算 離散數學第一章 第二張是答案可以參考～

b) X, 2-3, 3i 35 ; 1< 13. In how many ways can we distribute eight identical white balls into four distinct containers so that (a) no container is left empty? (b) the fourth container has an odd number of balls in it? nansion of

請問第44題要怎麼寫? 第二張圖是我的寫法，因為cu->cu2+發生氧化反應，所以另一個的氧化E°必須小於cu的,這樣cu才能發生氧化，請問這種想法是錯的嗎?? :(

44. Which one of the following reagents is capable of transforming Cu(s) to Cuf* (1 M)? A) I (1M) B) Ni(s) C) Ag" (1 M) D) AP* (1 M) E) Hf (1 M) Ans: C Category: Medium Section: 19.3 45. Which one of the following reagents is capable of transforming Fe3+ (1 M) to Fe2+ (1 M)?

第17合成函數前面有函數怎麼做？

8:20 ul 4G o moodle.chu.edu.tw 2.4節(p.154):7、31 1-22 Differentiate. 7. y = sec 0 tan 31. (a) Find an equation of the tangent line to the cury y = 2x sin x at the point (11/2, ). (b) Illustrate part (a) by graphing the curve and the line on the same screen. 2.5節(p.162):17、31 7-48 Find the derivative of the function. 17. h(v) = vž1 + y2 31. y = 1 + sinx COS 2.6節(p.170):31 (本題除了算出切線方程式 要用電腦畫出隱函數曲線與切線) 31. x² + y2 = (2x² + 2y? – x)?, (0,5) (cardioid) YA D 2.9節(p.197) :31、35 31-36 Use a linear approximation (or differentials) to est the given number. 31. (1.999) 35. tan 2° +

第二、三題求解，希望有過程拜託🙏

- Reader Touch. 天,然後休假兩天。該飯店客房部需決定至少僱用多少位員工,才能滿足每天的, 需求,試建構此問題之線性規劃模式?(20%) 三 四 五 日 星期 人力需求 14 10 11 13 16 20 18 2. 請分別以(1)高斯-焦丹法(2)克拉瑪法則(Cramer's rule)求解下列方程組。(30%) x1 + x2 + 2x3 = 8 -X1 - 2x2 + 3x3 = 1 3x1 - 7x2 + 4x3 = 10 3.利用M=[A]求出Al。(20%) 11 A= -2 11 11 1」 「1 + 2] ro 這裡輸入文字來搜尋 員 27°C A 6) 英

（社區） 求解🙏第71題：陰性預測值要怎麼算 謝謝！！

0267. 骨質密度篩檢之敏感度(sensitivity)為80%,其代表的意義為何?(A)篩檢結果為陰性個案中,有80%有骨質疏鬆 (B)有 80%的骨質疏鬆個案,篩檢結果為陰性(C)篩檢結果為陽性個案中,有80%有骨質疏鬆(D)有80%的骨質疏鬆個案,篩檢結 果為陽性。 情況:159 位喉嚨痛的病人中,有42位喉部培養呈陽性,在呈陽性反應者中經醫師正確診斷出B疾病者有30人;同時有117 人 喉部培養呈陰性,醫師對其中88 人正確地未給予抗生素(如表)。依此回答以下四題。 DID 升 68. 此喉部培養檢查的敏感性(sensitivity)是:(A) 50.84% (B) 71.42% (C) 75.21% (D)88%。 +3o 142 69.此喉部培養檢查的特異性(specificity)是:(A) 50.84% (B) 71.42% (C) 75.21% (D) 88%。 | 88 | 收 历 70. 此喉部培養檢查的陽性預測值(positive predictive value)是:(A) 50.84% (B) 71.42% (C) 75.21% (D) 88% 71, 此喉部培養檢查的陰性預測值(negative predictive value)是:(A) 50.84% (B) 71.42% (C) 75.21% (D) 88%。 72. 某地區年中人口數為10萬人,該地區肝癌病患為1,000人,全年內死亡總人數為500人,其中因肝癌死亡為30 人,該地區 肝癌致死率為何?(A)3%(B)30%(C) 5%(D)50%。 73. 斯徒昂特(Stuart)所提出家庭的五項特質,不包含下列何項?(A)家庭成員之間可能沒有血緣關係 (B)家庭成員可能沒有 = 3%0 住在一起 (C) 家庭成員可能沒有生育下一代 (D) 家庭成員之間可能沒有承諾與責任。 74. 卡加利家庭評估模式(Calgary Family Assessment Model)的評估架構中不包括下列何者?(A)家庭的優勢 (B)家庭的發展 (C)家庭的結構 (D) 家庭的功能。 391100/159 子女 XIE 14pp 众(information idlove)