為什麼[A(org)]=n[An(org)]成立 (第三張圖equation 7.9) 感謝

Experiment 7 Experiment 7 The partition of Organic acid between Water and Organic solvent Objectives Understand the partition of a solute between two immiscible solvents. Introduction A chemical analysis that is performed primarily with the aid of volumetric glassware (e.g., pipets, burets, volumetric flasks) is called a volumetric analysis. For a volumetric analysis procedure, a known quantity or a carefully measured amount of one substance reacts with a to-be-determined amount of another substance with the reaction occurring in aqueous solution. The volumes of all solutions are carefully measured with volumetric glassware. The known amount of the substance for an analysis is generally measured and available in two ways: 1. As a primary standard: An accurate mass (and thus, moles) of a solid substance is measured on a balance, dissolved in water, and then reacted with the substance being analyzed. 2. As a standard solution: A measured number of moles of substance is present in a measured volume of solution - a solution of known concentration, generally expressed as the molar concentration (or molarity) of the substance. A measured volume of the standard solution then reacts with the substance being analyzed. The reaction of the known substance with the substance to be analyzed, occurring in aqueous solution, is generally conducted by a titration procedure. The titration procedure required a buret to dispense a liquid, called the titrant, into a flask containing the analyte. A reaction is complete when stoichiometric amounts of the reacting substances are combined. In a titration this is the stoichiometric point. In this experiment the stoichiometric point for the acid-base titration is detected using a phenolphthalein indicator. Phenolphthalein is colorless in an acidic solution but pink in a basic solution. The point in the titration at which the phenolphthalein changes color is called the endpoint of the indicator. Indicators are selected so that the stoichiometric point in the titration coincides (at approximately the same pH) with the endpoint of the indicator.

想請問這題🙏，有點看不懂圖三的公式是從何而來，卡住了

EXAMPLE 21.11 FIELD OF A UNIFORMLY CHARGED DISK A nonconducting disk of radius R has a uniform positive surface charge density o. Find the electric field at a point along the axis of the disk a distance x from its center. Assume that x is positive. SOLUTION IDENTIFY and SET UP: Figure 21.25 shows the situation. We rep- resent the charge distribution as a collection of concentric rings of charge dQ. In Example 21.9 we obtained Eq. (21.8) for the field on the axis of a single uniformly charged ring, so all we need do here is integrate the contributions of our rings. EXECUTE: A typical ring has charge dQ, inner radius r, and outer radius r + dr. Its area is approximately equal to its width dr times its circumference 2πr, or dA = 2πr dr. The charge per unit area is σ = dQ/dA, so the charge of the ring is do = o da = 2πor dr. We use dQ in place of Q in Eq. (21.8), the expression for the field due to a ring that we found in Example 21.9, and replace the ring 21.25 Our sketch for this problem. Idr dQ X P dEx dEx radius a with r. Then the field component dEx at point P due to this ring is 1 2πσrx dr 4π€0 (x² + ²)3/2 SOLUTION Continued

化學 PH值計算（多質子酸解離） 請問這題錯在哪裡呢😭

0.3M Na2HPO4 Example #1: Determine the pH of 0.300 M sodium hydrogen phosphate, Na₂HPO4. Phosphoric acid, H3PO4, contains K₁₁ = 7.5 x 10-3, K₂ = 6.2 x 10-8 and K₁3 = 4.2 x 10-13. al a2 a3 x² 0.2x=4.2X10-13 x² = 1.26×10-¹3/- 0.₁126×10/2 x = 0.355x100 HP04² = H30t+ P04² 0.3 0.3-X +x +X X X 3- 04-beg[+0]- (6.459.78 PH= Simp -6

（普物-光的折射） 請問這題要怎麼解 位置跟大小都需要解答 感謝🥲

EXAMPLE 34.11 An image of an image Converging lenses A and B, of focal lengths 8.0 cm and 6.0 cm, respectively, are placed 36.0 cm apart. Both lenses have the same optic axis. An object 8.0 cm high is placed 12.0 cm to the left of lens A. Find the position, size, and orientation of the image produced by the lenses in combination. F₁ 2 Lens A 12.0 cm 8.08.0 cm cm F2 -24.0 cm- 36.0 cm FL 3' 2' 3. 1' Lens B 3,1% 2' -3' F₂ 12.0 cm*12.0 cm K6.0><6.0 cm cm I' 23

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Compound semiconductors can be doped to make n-type and p-type materials, but the scientist has to make sure that the proper atoms are substituted. For example, if Ge were doped into GaAs, Ge could substitute for Ga, making an n-type semi- conductor; but if Ge substituted for As, the material would be p-type. Suggest a way to dope CdSe to create a p-type material.

只有氧是不規則的命名嗎？ Tetroxide vs tetraoxide Pentoxide vs pentaoxide PCl5 後面Cl 就是 pentachloride

6 机 BLE 2.6 | Prefixes Used to Indicate Number im Chemical Names U選4 7)o7o- g- 7二 Numberindicated 1 7efrg- 2e77o- Agexog- 7epfg- Ocfg- 7o7g- 選和os和 eu |,, decg- INTERACTIVE EXAMPLE 2.8 SOLUTION JPHABnEB 呈_Atomsg, Miolecules, and Ins consider the names ot the s will no To see how these Tules apply, 沿 同 lent compounds formed by nitrfgg 時 as tematic Name 了 同 loxi Nitrous oX1ce de 。 imitrogen InonoX1 1 9 ii monoxide NI 時 4 NO Nitrogen N os Dinitrogen TioX1 同 Noo, Dinitrogen tetIOX1 Noo Dinitrogen pentoxi 2 avoid awkward pron that to hen the element beglns Wtt 7oO/ dinitrogen tetrdox ng examples fthe prefiX trogen tetroxide, tt their common names- esystematic names to Notice from the precedi often drop the final ? % 20 example, N204 1S called dinlt called carbon monoxide, 7 carbo Some compounds are always Te are water, ammonia, and hydrogen pe H2O2 are never used. n monoox1l ferred to by roxide- Th Naming Type 山 Binary Compounds 1. Name each of the following compounds: a. ,PCD DBGIG MS 09 2. From the following systematic nameS, Write the formula for ea a.。 Sulfur hexafluoride b. Sulfur trioxide c.。 Carbon dioxide 1 Formula Name a. PCl Phosphorus pentdehloride Be Phosphorus trichloride c. SO2 Sulfur dioxide 2. Name Formula a.。 Sulfur hexafluoride SFe b.。 Sulfur trioxide SO ce. Carbon dioxide CO

4.59答案為什麼是a

mass, are 「 PASSAGE PROBLEMS 了 R/S BODY. Dancers experience jjmps they make. Tor example Speed7 sma- jZOnta] ) case7? he box )n foT 7 ere no an en- )1S at- 了1S and 1S Ve Up- glvVen 「graph 1 TV planet, when a dancef ]an head by 過e neck cause 負e head to $ 9g.4% of atypical personsm Janding after a Vertical Jump $ 4.0 m/s to restinatime of 0.20 S. 4,57 What 1$ the magnitude Of the average force that her neck exerts on her head during the ]anding? (3) ON; (b) 6O N; (c) 120 N: must exceed the jow down and come to Tes- The head is about as8. Video analysis ot a 65-kg dancer hows that her head decelerates from hthe force her neck exerts on her head during the ]anding, the force her head exerts On her neck 1S (3) the Sames: (b) greater; (co) smaller: (d) greater during the first half ot the land- uring the second halt of the ]anding. 4.,58 Compared Wit 9 and smaller d 4,59 While the dancer 1S in the air and holding a fixed bose what is the magnitude of the force her neck exertS On her heady (3 ON; (b) 6O N; (o]) 120 N; (0) 180 N. 4.60 The forces ona dancer can be measSsured directly When a dancer performs aJump On a force plate that measSures the 10rfce betWween her feet and the ground. A graph Of force verSus time es a Vertical jump performed on aforce plate is Shown lt es at 1S happening at 0.4 $? The dancer is (3) bendlng 0 1S acceleratling downward; (b) pushtung er legs and is almost ready to leave the ground (o in the air and at the to have just touched the 一 her jump; (d) landing and her feel Figure P4.60

62題麻煩了~~

]ate the solubilty product 人ip for Nis at 20 “C. CC 62. Most hydroxides are hot Very soluble in water. For example “for nickel(HLD hydroxlde, NI(OH)2, is 2.0 X 10 Pat25 日ow many gramsSs Of nickel(HD) hydroxide disSolve per liter at ge 歸, 還 悶 汪 2 比