想請教計算方法，目前求得莫爾比但後續處以0.18（化整數）時感覺很怪，題目要求120克pan的經驗式，但我化完整數後光是C+H前兩項的質量就會超過120克了，想請教各位如何計算

C z Hz N O S o f 3.44 Peroxyacylnitrate (PAN) is one of the components of smog. It is a compound of C, H, N, and O. Deter- mine the percent composition of oxygen and the empirical formula from the following percent composition by mass: 19.8 percent C, 2.50 percent H, 11.6 percent N. What is its molecular formula, given that its molar mass is about 120 g?

想問問這題怎麼算

4. 在本實驗中5微升(1L=10-6L)溶液約可產生一個直徑0.5公分的斑點,如果硝 酸銅溶液濃度為6.5g Cu²+/L,試問每一斑點中含銅離子若干微克? m 5,2ma

看不懂老師的算式 有人能幫我拆解步驟解釋一下嗎 或是另外寫易懂的算式過程 拜偷

A sample containing 25.14g of neutral salts, glucose and a sodium carbonate/bicarbonate buffer was dissolved in 100 ml of water. A 25 ml aliquot of the resultant solution required 20.35 ml of 0.0987 M HCl when titrated to the PP end-point. A second 25 ml aliquot was titrated to the MO end-point and required 56.75 ml of the acid. Calculate the percentage of Na2CO3 (molecular weight 106) and NaHCO3 (molecular weight 84) in the sample. 含有25.14克中性鹽、葡萄糖和碳酸鈉/碳酸氫鈉的樣品將緩衝液溶解在100ml水中。需要25毫升等份所得溶液滴定至PP終點 時,使用20.35ml 0.0987 M HCl。第二份25毫升等分樣本是滴定至MO終點,需要56.75ml酸。計算百分比樣品中的Na2C03 (分子量106)和NaHCO3(分子量84) 39

請問SO3 VSEPR 怎麼畫

x3):0 个 个 P P 可 个 邛 z 618 80 > 24 - (8x3) = 0 AX3 0.25*2pt 0.⁰00 Jsp ² SP 4 " 化化个 久 P spa sp 24

想問收斂到...這行怎麼看出是n(n+1)/2的？

(n) = T(n-1) +n, T(0) = 0, T(1) = 1 T(n) = ?, 0(?) big-on ? 军: T(n-2) +in- (n) =T(n −1)+n » TCn 3) An 21-19 tới 1B) = (T(n − 2) + n-1) + n = (T(n − 3) + n-2) +n-1+n = (T(n −4) + n-3) + n-2+n−1+n . M :NU2/5/231) T(n_n) +n+h-1th-2 +---+ | = T(n − n) + 1+ 2+ 3+ + n =0+1+2+ … + n (1 + n)n 2 = ⇒ O(n²) nunti) 2 = Ten) = // 24² +12/201

請教小試身手第3題的第1小題~~感謝😆 （因為高中沒有資訊相關的科目，所以在此提問

小試身手 1. 下列 C/C++ 運算式的x值為何? 1203 (1) x = 7/2 2. 請將下列式子使用C/C++ 的運算式表示。 * * (2)bmi = (1) a = wr (2) x = 3 * 5 % 2 - 1 rr. (1) cout << x << y; 12. h W² 阿 3.若 x = 1, y = 2,下列 C / C++ 敘述輸出的結果為何? 0 h/(w*w). (2)cout << "x + y =" << x + y; 3.

請問第39（1）怎麼計算⋯？🙏😭

TOOTH tools to Across a thin cell membrane, the solution pH changes from 7.2 to 5.2, Calculate the electric potential difference across the membrane. Ans.0.59210 Juoi blogs (2) Which side (7.2 side or 5.2 side) has a higher potential? ole (1)0.11832V; obri. (2) pH = 5.2 VI VARI 12 Lynsm wol/25 (103台大A) osups mis 5.2

想請問這個表格上寫的 "fold reversal "是什麼意思 要怎麼翻譯比較好，謝謝（有上網查過了，但不太了解）

Pro DC 箱(W) 說明(H) nib).pdf x ↑ X gs 638 (3/14) 125% ... Table 1. Effect of lazertinib on reversing the MDR mediated by ABCB1 or ABCG2 in drug selected resistant cancer cells IC 50 ± SD (µM) (fold reversal) Compounds KB (parental) KBv200 (ABCB1) Vincristine 0.0059 +0.0323 (1.00) 0.2263 ± 0.0323 (1.00) +0.0625 µM Lazertinib 0.0053 ± 0.0003 (1.12) 0.0041 ± 0.0002 (1.43) 0.0782 +0.0182** (2.89) 0.0195 ±0.0105** +0.125 µM Lazertinib (11.60) 0.0090 0.0011** (25.21) +0.25 µM Lazertinib 0.0050 +0.0007 (1.54) 0.0042 ± 0.0002 (1,47) 0.0100 ± 0.0038** (22.60) +10 µM Verapamil Doxorubicin 0.0218 ± 0.0038 (1.00) 1.2091±0.4592 (1.00) +0.0625 µM Lazertinib 0.0216 ± 0.0093 (1.01) 0.4347±0.0807** (2.76) +0.125 uM Lazertinib SD alo and *p exp tor res an apy ure wh ing E Confe 100% M C 從表1年 對受質車 ABCG2 然而·L= 劑的IC5C 藥物敏感

水文學——降水與損失 如圖，請問有人知道這兩題該怎麼算嗎？ 翻遍教科書教過的內容根本沒想法⋯

> 0 2-14 有一矩形集水區,其四個角落的座標分別為(0,0),(0,10), (14,10) 和 (14,0)。集水區內設有四個雨雨量測站,各測站所在位置的座標及降雨量如下 表。所有座標值的單位均為公里。試以徐昇氏法推算此集水區的平均降雨量 及逕流總體積(註:假設無任何降雨損失) o 雨量站位更 (4,2) (4,7) (11 , 7) | (11,2) 降雨量(cm) 1.5 2.0 2.4 4.3 ( 86 水利工程簡任升等)

沒有頭緒，請問怎麼解題🙏

5. 2.56* Show explicitly, that the function ř, t) = A exp[i(:Ť + wt + ε)] describes a wave provided that v = w/k. -