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自然科學 大學

為什麼[A(org)]=n[An(org)]成立 (第三張圖equation 7.9) 感謝

Experiment 7 Experiment 7 The partition of Organic acid between Water and Organic solvent Objectives Understand the partition of a solute between two immiscible solvents. Introduction A chemical analysis that is performed primarily with the aid of volumetric glassware (e.g., pipets, burets, volumetric flasks) is called a volumetric analysis. For a volumetric analysis procedure, a known quantity or a carefully measured amount of one substance reacts with a to-be-determined amount of another substance with the reaction occurring in aqueous solution. The volumes of all solutions are carefully measured with volumetric glassware. The known amount of the substance for an analysis is generally measured and available in two ways: 1. As a primary standard: An accurate mass (and thus, moles) of a solid substance is measured on a balance, dissolved in water, and then reacted with the substance being analyzed. 2. As a standard solution: A measured number of moles of substance is present in a measured volume of solution - a solution of known concentration, generally expressed as the molar concentration (or molarity) of the substance. A measured volume of the standard solution then reacts with the substance being analyzed. The reaction of the known substance with the substance to be analyzed, occurring in aqueous solution, is generally conducted by a titration procedure. The titration procedure required a buret to dispense a liquid, called the titrant, into a flask containing the analyte. A reaction is complete when stoichiometric amounts of the reacting substances are combined. In a titration this is the stoichiometric point. In this experiment the stoichiometric point for the acid-base titration is detected using a phenolphthalein indicator. Phenolphthalein is colorless in an acidic solution but pink in a basic solution. The point in the titration at which the phenolphthalein changes color is called the endpoint of the indicator. Indicators are selected so that the stoichiometric point in the titration coincides (at approximately the same pH) with the endpoint of the indicator.

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自然科學 大學

分析化學 拜託好心人士可以教教我🙏 高職畢業沒有基礎 老師又沒有教怎麼算 自己讀過還是看不懂🥲

22 分析化學 習題五 1.依據下列反應,以酸的式量的分數或倍數表示其當量: UHSOX+KOH-KHSO+HO (b2LOH + H.PO-Li HPO+2HO (c) Ba(OH)+2H1O, Ba(10)+2H.O id Na CO,+2HCICO+ HO+2NaCl 52 計算下列的毫當量數: (fw HSO) (fw H.PO/2) (fw HIO) (fw HC) (a)06498克的HgO,作爲滴定酸的一級標準: HgO+2HO° +4Br=HgBr²+3HO (07644克的AgNO作路硼氫的還原劑: 8Ag¹+BH +80H 8Ag+H.BO, +5H₂O (c)04602克NaH.PO+2HO發生下列反應: H.PO. +OHHPO (295) 53 500ml水溶液含921g K.Fe(CN),用下列方式表示溶液的濃度: (0.06M) (a)莫耳分析濃度 (blkº莫耳濃度 (02M) (c)關於下列反應的當量濃度 MnO+5Fe(CN) +8H" == Mn'" +5Fe(CN)+4HO【006M) 54 將877g KH(10)溶於水配成500ml溶液,用下列方式表示溶液的 (a)莫耳分析濃度 [0045M] 〔0.09M] (BIO 莫耳濃度 (c)用作酸的當量酒度 [0045M] (①用作下列反應之氧化劑的當量濃度 JO"+HNNE+2H' +2C=IC +N+3HO (0361) 5-5配製1000ml的004N KI溶液,需多少克KI? (a)氧化成 (664) (60) 第三篇 第五章 容量分析简介 243 (0.83g) (0.204g) (0.208g) (0.308g) (0.384g) (0.048g) [0153g] (1198) (135g) (1418) (18.8ml) (18.8ml) (22.4ml) (51.69ml) (28.78m1) (bIT 氧化成ION 56在48600m170005N溶液中含有多少克洛買? GalNaHCO (b) Ba(OH) (c)(產物IC) (d) Na.S.O. (S.o/ ) {elNaSO(產物SOP) (NaSO(或物SOF) 57 由下列試劑配製滴定濃度 40mgHNO/ml的溶液25000ml la) KOH UKI(產物NO及L) (KMnO(產物NO"及Mn") 团Ce(SO)(產物NO"及Ce") 58 計算0112N NaOH與下列溶液反應所需之體積 (a)2500ml的 0.084NHCIOL (b) 25.00m10 0.064N H.SO. (c)09783g的KH(IO) (d)03126g的H.COHO(產物CO) e04448g的NaH.POHO (產物HPO)

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