請問有誰會呢 求解 🙏🙏

北「9) 化令到的10PBC (0) CH CH (b) HAC •CHA CH (d) CHg -CH3 (e) Hoch "CM3 2.5% - Jul - 1,3-二甲基银己或反 15-三甲基德,何差较穩定。 式出名的构式構形,多年舞。 2159-*** Pujuk Git the Bay of (malío acid C4 1005). o y os olet ze by bank in 64 wh k tě { - 12 = 120% hep eh na 10 - CO-HA) (4) 新北至少五律预算的可能。 (b) 40 最早也是一种KAI有一個 | | 連結在一反上) 41集結構何? b) - 試結出行的一種精幕,五指出一種較穩定。 CH3 行 HO CH(CH3)2

有人知道圈起來的地方的意思是 AgI質量乘 142/233＝新生成的AgCl質量嗎？ 所以這一串式子是原本的AgCl質量再加上後面進行反應新生成的AgCl質量嗎？

4-17. A 0.6407-g sample containing chloride and io- dide ions gave a silver halide precipitate weigh- ing 0.4430 g. This precipitate was then strongly heated in a stream of Cl2 gas to convert the Agi to AgCl; on completion of this treatment, the precipitate weighed 0.3181 g. Calculate the per- centage of chloride and iodide in the sample.

大學普化 方智化學第六題

ow Na k 7 CI o se Br Chapter 2 化學鍵結 AH -C=CH 升二技插大 3. Brigma The bond between the carbon atoms in acetylene (HCCH) consists of ) (A)6 pi electrons (B)4 pi and 2 sigma electrons (C)6 sigma electrons (D)2 pi and 4 sigma electrons (E)3 pi and 3 sigma B) B 7.(BCDE) electrons. 【84 成大化學) 14.(B) 20.(C) 4. E ) (A)NO; [83 中興A] Which of the following has a triple bond? (B)O2 (C)C12 (D)CO; (E)CN-. Which one of the following element pairs has the lowest electronegativity (B) 27.(D) 34. (C) C) 41.(CD) 1 G difference and thereby is the least polan? Få 10 323.49 B) (84 5% *ILI) -) 48. (A) 6. NET 2 > 2 D) 58. (D) 62. (B) 69. NO+ D Obind (219) O 发 (A)SeF (B)Seci (QKBr (D/NaCl (E)KAT. 11 The compound Sio does not exist as a discrete molecule while CO2 does. This can be explained because ly 2 ep 3 15 aly zp (A)the Si–O bond is unstable (B)The Lewis structure of SiO has an even number of electrons (C)The SiO2 is a solid while CO, is a gas (D)the 3p orbital of the Si has little overlap with the 2p of the 0 (E)none of the these. V MOJT 515 1 - 4 40 (成大】 Yi (4 0 atom) (86 58*A] 7. In order to explain the valence observed for many of the elements 0 -Si-O in terms of electron configurations, it is often useful to look at electronis staies slightly different from the ground state in comparing 0-41-0 the ground state of boron with the state more useful to describe 0 bonding, the number of unpaired electrons goes from (A)1 to 2 (B)1 to 3 (C)3 to 4 (D)3 to 5 (E)none of the above. (集 (80 清大B) Which of the following compounds should not exist? ( (, 【85 成大A】 alf 566-32 Cle 32-8-24 2-89 cild 14 1 he atoms 83 中興A) mm bove. B 29 p. 1 1 be a ) \CHE > ? (A)Na,P (B)(NH4),PO, CIPO. DPH xH)POCI,, Maspal sput 中興A] Pa zorgt O 15412 = 1) O-P- 5 5+12= 1) 10-4 - 13 13-12=1 -- cl-P-0

請問第44題要怎麼寫? 第二張圖是我的寫法，因為cu->cu2+發生氧化反應，所以另一個的氧化E°必須小於cu的,這樣cu才能發生氧化，請問這種想法是錯的嗎?? :(

44. Which one of the following reagents is capable of transforming Cu(s) to Cuf* (1 M)? A) I (1M) B) Ni(s) C) Ag" (1 M) D) AP* (1 M) E) Hf (1 M) Ans: C Category: Medium Section: 19.3 45. Which one of the following reagents is capable of transforming Fe3+ (1 M) to Fe2+ (1 M)?

求解 謝謝

The figure shows a three-particle system, with masses mu = 4.2 kg. m2 = 2.8 kg, and m2 = 7.3 kg. What are (a) the x coordinate and (b) the y coordinate of the system's center of mass? 13 2 1 x (m)

《普通化學》第九題跟第十題，感恩。

Alinie 2 PBurel H12 lapf Setul lagly x2 e determined by titfátinga 100 sample of KCror. Nos cag & beth 14 raqla 1: 191 +24100) No. (aq) + 2 Al Al EX Mn of laql4 2 1 7 Mn Oz (s) + Al(Orta 9. The blood alcohol (C2H5OH) level can be potassium dichromate solution, resulting in the production of Cr3+ (aq) and carbon dioxide. The reaction can of blood plasma with an acidic be monitored because the dichromate ion. (Cr20,?) is orange in solution, and the Cr" ion is green. The unbalanced redox equation is C₂H5OH(aq) + 3H₃0 (aq) + 2 CO2 (g) +12Hg) Me Cr2O,?- (aq) + CHșOH (aq) --Cr"(aq) + CO2(8) 14 Heag toe Cruon Lafla203149) If 31.05 mL of 0,0600_M potassium dichromate solution is required to titrate 30.0 g of blood plasma, Hamm Fapter (aq) determine the mass percent of alcohol in the blood. 0.143% Ca H5OH. 2- tize 32.0 g 10. An average human being has about 5.0 L of blood in his or her body. If an average person were to eat ht of sugar (sucrose, C12H22011, 342.30 g/mol), and all that sugar were dissolved into the bloodstream, how would the molarity of the blood sugar change? HO +1 HO +1 H &H to H - 31 OH HO HIP 126 0 HO +1 + 5e OH OH OH (+36 ) x2 t6 Cr2O7 - 20+ 3+

請教一下，我今天做到一個實驗是酸鹼滴定實驗，但我忘了圖上要的酸度與鹼度的定義是甚麼？我覺得我的數據有點奇怪，正常來說，算％會到124％嗎？

万粉 度(%) 酚酞指示劑 滴 ·食醋的酸度測定 1009.49 . 5 b 6 soo 1. 1ooo CH 0.0012 x16Q、 0,12%. 1008 -x100 CH3COOH 1000 X 100 CH3COOH(ml) 20 0.6 the = 12 % 氫氧化鈉(NaOH) 食醋 甲基橙 實驗步驟 to = 4 1000 40.9 too 29 取一乾淨5ml 刻度吸量管,精確吸取 5ml 的食醋於250ml 錐形瓶內,加入約100ml 的純水,使 49 起充分溶解,再加5滴酚酞指示劑(溶液為無色)。 已知濃度 0.1N 的NaOH 的標準溶液滴定至溶液成粉紅色為止。 3. 假設食醋的比重是1.00,依下式計算食醋的酸度: 0-1 x Nox NbxV 酸度(%)= 3 4. 重複實驗一次,求出食醋中的酸度平均值(%) - 二、去污粉鹼度測定 1. 稱取約0.25g的家庭用去污粉倒入250ml 錐形瓶內,加入約100ml 的溫水,使起充分溶解,冷 卻後再滴5滴甲基橙。 vol 2. 已知濃度 0.1N 的 HC1 的標準溶液滴定至溶液成橙色為止。 (600 3. 依下式計算去污粉的酸度(Na2O計): 36.5 NaxVa> 鹼度(%)-- X 100 [00 3.65 x2 Na2O(g) 4. 重複實驗一次,求出去污粉中的鹼度平均值(%) 200 7.30 slxy F1 249)) 62 3lio.25 NX Too x Toro | Na20 2000 32 al XIX 29 Xyup.

水文學——降水與損失 如圖，請問有人知道這兩題該怎麼算嗎？ 翻遍教科書教過的內容根本沒想法⋯

> 0 2-14 有一矩形集水區,其四個角落的座標分別為(0,0),(0,10), (14,10) 和 (14,0)。集水區內設有四個雨雨量測站,各測站所在位置的座標及降雨量如下 表。所有座標值的單位均為公里。試以徐昇氏法推算此集水區的平均降雨量 及逕流總體積(註:假設無任何降雨損失) o 雨量站位更 (4,2) (4,7) (11 , 7) | (11,2) 降雨量(cm) 1.5 2.0 2.4 4.3 ( 86 水利工程簡任升等)

求解 答案1/6

Go Figure Estimate the fraction of molecules at 100 °C with speeds less than 300 m/s. Ump At 0 °C, fewer than half the molecules move at speeds greater than 500 m/s. At 100 °C, more than half the molecules move at speeds greater than 500 m/s. the speed exhibited by the largest number of molecules Uav = the average (mean) speed of all the molecules Urms the speed of a molecule whose kinetic energy is equal to the average (mean) kinetic energy of all the molecules 0 °C 100 °C | || Fraction of molecules Fraction of molecules | || 11 1 |||| 11 0 0 5 X 102 10 X 102 Molecular speed (m/s) (a) 5 X 102 10 X 102 Molecular speed (m/s) (b)

有人知道我是哪裡算錯嗎(ಥ_ಥ)

= 78, When the electron in a hydrogen atom falls from the n= 3 excited energy level to the ground state energy level, a photon with wavelength 2 is emitted. An electron having x this same wavelength would have a velocity of A) 7.10 x 10 m/s. D) B) 2.93 x 10 m/s. E) C) 2.93 x 103 m/s. Ans: A Category: Medium Section: 7.4 7.10 m/s. 3.00 x 108 m/s.