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自然科學 大學

分析化學 拜託好心人士可以教教我🙏 高職畢業沒有基礎 老師又沒有教怎麼算 自己讀過還是看不懂🥲

22 分析化學 習題五 1.依據下列反應,以酸的式量的分數或倍數表示其當量: UHSOX+KOH-KHSO+HO (b2LOH + H.PO-Li HPO+2HO (c) Ba(OH)+2H1O, Ba(10)+2H.O id Na CO,+2HCICO+ HO+2NaCl 52 計算下列的毫當量數: (fw HSO) (fw H.PO/2) (fw HIO) (fw HC) (a)06498克的HgO,作爲滴定酸的一級標準: HgO+2HO° +4Br=HgBr²+3HO (07644克的AgNO作路硼氫的還原劑: 8Ag¹+BH +80H 8Ag+H.BO, +5H₂O (c)04602克NaH.PO+2HO發生下列反應: H.PO. +OHHPO (295) 53 500ml水溶液含921g K.Fe(CN),用下列方式表示溶液的濃度: (0.06M) (a)莫耳分析濃度 (blkº莫耳濃度 (02M) (c)關於下列反應的當量濃度 MnO+5Fe(CN) +8H" == Mn'" +5Fe(CN)+4HO【006M) 54 將877g KH(10)溶於水配成500ml溶液,用下列方式表示溶液的 (a)莫耳分析濃度 [0045M] 〔0.09M] (BIO 莫耳濃度 (c)用作酸的當量酒度 [0045M] (①用作下列反應之氧化劑的當量濃度 JO"+HNNE+2H' +2C=IC +N+3HO (0361) 5-5配製1000ml的004N KI溶液,需多少克KI? (a)氧化成 (664) (60) 第三篇 第五章 容量分析简介 243 (0.83g) (0.204g) (0.208g) (0.308g) (0.384g) (0.048g) [0153g] (1198) (135g) (1418) (18.8ml) (18.8ml) (22.4ml) (51.69ml) (28.78m1) (bIT 氧化成ION 56在48600m170005N溶液中含有多少克洛買? GalNaHCO (b) Ba(OH) (c)(產物IC) (d) Na.S.O. (S.o/ ) {elNaSO(產物SOP) (NaSO(或物SOF) 57 由下列試劑配製滴定濃度 40mgHNO/ml的溶液25000ml la) KOH UKI(產物NO及L) (KMnO(產物NO"及Mn") 团Ce(SO)(產物NO"及Ce") 58 計算0112N NaOH與下列溶液反應所需之體積 (a)2500ml的 0.084NHCIOL (b) 25.00m10 0.064N H.SO. (c)09783g的KH(IO) (d)03126g的H.COHO(產物CO) e04448g的NaH.POHO (產物HPO)

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自然科學 大學

大學普化 方智化學第六題

ow Na k 7 CI o se Br Chapter 2 化學鍵結 AH -C=CH 升二技插大 3. Brigma The bond between the carbon atoms in acetylene (HCCH) consists of ) (A)6 pi electrons (B)4 pi and 2 sigma electrons (C)6 sigma electrons (D)2 pi and 4 sigma electrons (E)3 pi and 3 sigma B) B 7.(BCDE) electrons. 【84 成大化學) 14.(B) 20.(C) 4. E ) (A)NO; [83 中興A] Which of the following has a triple bond? (B)O2 (C)C12 (D)CO; (E)CN-. Which one of the following element pairs has the lowest electronegativity (B) 27.(D) 34. (C) C) 41.(CD) 1 G difference and thereby is the least polan? Få 10 323.49 B) (84 5% *ILI) -) 48. (A) 6. NET 2 > 2 D) 58. (D) 62. (B) 69. NO+ D Obind (219) O 发 (A)SeF (B)Seci (QKBr (D/NaCl (E)KAT. 11 The compound Sio does not exist as a discrete molecule while CO2 does. This can be explained because ly 2 ep 3 15 aly zp (A)the Si–O bond is unstable (B)The Lewis structure of SiO has an even number of electrons (C)The SiO2 is a solid while CO, is a gas (D)the 3p orbital of the Si has little overlap with the 2p of the 0 (E)none of the these. V MOJT 515 1 - 4 40 (成大】 Yi (4 0 atom) (86 58*A] 7. In order to explain the valence observed for many of the elements 0 -Si-O in terms of electron configurations, it is often useful to look at electronis staies slightly different from the ground state in comparing 0-41-0 the ground state of boron with the state more useful to describe 0 bonding, the number of unpaired electrons goes from (A)1 to 2 (B)1 to 3 (C)3 to 4 (D)3 to 5 (E)none of the above. (集 (80 清大B) Which of the following compounds should not exist? ( (, 【85 成大A】 alf 566-32 Cle 32-8-24 2-89 cild 14 1 he atoms 83 中興A) mm bove. B 29 p. 1 1 be a ) \CHE > ? (A)Na,P (B)(NH4),PO, CIPO. DPH xH)POCI,, Maspal sput 中興A] Pa zorgt O 15412 = 1) O-P- 5 5+12= 1) 10-4 - 13 13-12=1 -- cl-P-0

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