年級

科目

問題的種類

自然科學 大學

求全部詳解,在線等,急QQ(可以部分就好QQ

Pt 謹., 【G@放|中葉生說1 2018-test2-ch26-30 - 訪取0專用 入 圖 器 當數: so=8.85x1072F/m 一、選擇題:每題5分。 1一平行板電容器,若其每板面積為 100 cm?、兩板相距2mm。用 80V 的電池充滿電後,電容上的電荷量為: 0885nc; (8) 177nc;(c)354nc;(0) 708nc (51416nc。 2 南顆電容 G =10uF、G0=20 jiF 串聯後再連接一烽 12 V 的電池。求兩顆踢容總共儲存的能星。 多360p; 480nJ (0) 600nJ; (0) 720 1; (E) 840nJ。 3 一2hF 的平行板電容器,將其連接至 200V 的電池,充滿電後, 不移開。再將介電常數 <=10 的電 介質填滿十板間的空間,則此時電容儲存的艇量為多少?(多005J;(8) 01J;(c) 02J;(D) 04J; 四08 J 4 如右回,電容 帶電 0-8hC,電容 3C不帶電。將開辣閱上,經很久達平衡(此時電流為零)。若C=1hF,則從開始到最終 平衡時,電月R總共消耗的能星為 (8mJ; (8) 12mJ3 (0 16m (0) 20m0; 24nJ。 5 一 吃放電線路 :A=104Q,C=200 hF,電容的初電荷為10 mc。/=0 時,開始放電,則/=2s時,電流為 (人 184mAy 個368mA;(c) 539mA;(D)717mA; (E 904mA2 6一電荷 ?,其骨時速度# = 玉m/s,位於均勻磁場中2-(F+ 縣 245T,則其受力了= (CC2二片絡 (2C244片3 (02C2二中遇 (0)22中片朮(5202中4此嫩 7 一電子(=91x103 kg 7= 1.6x10? 0)以 1.2X10? m/s 的遠率進入一均勻磁場區域內作圓周運動磁場方向與速度方向垂 直, 若磁場大小為 01T,則其財期為 (A 12x1009s7 (8)36x100s; (tc)62x1006s;(0)76x1030s (四97x1009s。 8右圖中立方體的邊長為 40 cm, 電流 /= 10 A, 均勻磁場 52=02T, 則 09 段受到的磁力為: 人(95(症生N (80s(二全N3 (095二生N) (Do9sFN3(ED-95N3 二、計算題 1. Foureapactors are connectedas shownimnFig 1 Take Go 4pnF,人6 @2nF, =2nFande=14V Fmnd (the equivalentcapacitance;(b) the charge on Gi (c) the potentaldifferenceacross @(12仿 2 Forthe Acchargng crcutofFig 24akeA=100kg,c= 2nF,ande=20V heswitchisclosedat/=0.Fnd (a) tme constant tb) he maximum charge and curent (c) the charge on ihe capacftorat/=015(d) hecurentat/015(@ thepowerimthebatteryat/=01s。(20幼 3 Find (a) the currents 4、&and 6; (b) the potental difference between ponts 2and cinFig 3.(15 約 4 圖四的電路,將開關關上,經很久以後,(a)電流 +、/Z各為何 ? (b)電容上的電荷量為何 ? (c) 今將開關打開 ,則經多久後電容 的電荷量為10uC。(12 爺 5 如圖五,兩根通電流的長直導線:4=3Aand&=5A。若 7= 20 cm,求 人點磁場及與吃。(10 分)

待回答 回答數: 0
自然科學 大學

求解圖裡UICK quiz的第二小題

acit0r 1taneOuls CUrTent Differentiating Equation 27.22 with respectto time gives the inst: as afunction of time: 4 tt號 一Fe ptasafurc 主二 where Q;/有CC 三方 is the initial current. Figure 27.15b 5 in the resistor that we guessedin order to-apply Kirch Equations 27.15 and 27.21. Equation 27.23 shows that the ci ing capacitor is negative, indicating that the current 1s Figure 27.15c. Both the charge on the capacitor and the ct tially at a rate characterized by the time'constant7了三用C. 人 i 一 GOuicK ouiz 27.5 Considerthe circuitin Figure 27.17 and assume the battery has after the switch is closed, what is the currentin the Figure 27.17 no internal resistance. () 」 battery (a) 0 (b) &/2A(G 28/Z04 8/元(e) impossible to determine (ii) After a 有 eyerylong time, what is the Currentin the battery? Choose from the same choices. theswitch is CC (3 前:銜1加信介2放 IntermittentWindshield Wipers nobiles are equipped with windshield wipers that can operate intermittently during alight rainfall. How does ofsuch wipers depend on the charging and discharging ofacapacitor7 民 The wipers are part ofan 及C circuit whose time constant can be varied by selecting different values of及through amultipo- Sition sWitch. As the voltage across the capacitor increases, the capacitor reaches a point at which it discharges and Higgers the wipers. The circuit then begins another charging cycle. The time interval between the individual sweeps of the wiperS 1 determinedjby the value ofthe time constant.

待回答 回答數: 0