沒給角度要怎麼算啊?

Force R is the resultant of two forces P and Q. If the magnitudes of R and Q are 15 N and 7.32 N, respectively, determine (a) the magnitude of P; (9.93 N or 17.25 N) (b) the projection of R onto the direction of P. (13.6 N) B P 0 a R

請問紅色圈起來的地方是為什麼？ 謝謝🙏

7−(−2+h)— √7−(−2) h −1 −1 √9-h+3 V9+3 My Ax As h→0. = 9-h-3 h 6 = 9-h-3√9-h+3 (9-h)-9 -1 = √9+h+3h(√√9+h+3)¯¯ √√9+h+3² Th ⇒ at P(-2,3) the slope is =

想問第42題

25. lim 8118 27. lim X18 A 29. lim 31. lim 33. lim √x - √√x x→→∞ √√√x + √√x 35. lim 2x²/3 - x1/3 + 7 xxx x8/5 + 3x + √x 37. lim x→∞ x + 1 39. lim x - 3 x→∞ √4x² + 25 1 x→0+ 3x 1-x² 2√x + x¹ 3x - 7 41. lim 1. 2 X-2 X- 43. lim √x² + 1 45. a. lim 3 2x x-8+ x + 8 + 7x 4 x→7 (x-7)² 2 2 46. a. lim x-0+ x1/5 4 2 x-0+ 3x¹/3 B Infinite Limits Find the limits in Exercises 37-48. Write ∞ or -∞ where appropriate. 5 x →0-2x x - 3x 26. lim√√³+x-2 b. lim 2 + √x x→∞ 2 - √x 28. lim 30. lim x¹ + x4 x-xxx-²-x-3 32. lim Vì - 5x + 3 x-∞ 2x + x2/3 - 4 34. lim 36. lim 2 x→0 3x¹/3 xxx +1 2 b. lim x→0 x1/5 4 - 3x3 x-∞ √6 +9 38. lim 40. lim √x² + 1 42. lim x-3x - 3 3x x-5-2x + 10 44. lim -1 x→0 x²(x + 1) 19 lime 1

請問c怎麼寫？

e 2. Simplify each expression. Write your answer without negative exponents. (a) √200 √32 = 10√2 - 4√₂ = 6,W² (b) (3a³b³) (4ab²)² = 48 (a³ b') (ab ²)² = 48 9²³ 6² 95 2632 216 2443 L (c) ( 3x³/2y X² ,-1/2 -8 943 -1 3 (XXX)" (X^X^)" (²/²)^ x4 y

如圖，我不知道該怎麼證明它(ಥ_ಥ)

Example lim x 4. x-2

求解！找挖洞的球體體積的積分！這真的完全看不懂(ಥ_ಥ)

自一個半徑爲b之球,若我們從通過球心鑽一個半徑 a之圓洞後,求球剩下來之體積 “爲何?

求解答，二變數函數的偏微分

du 2. u=x² * (1) x (2) du dy du (3) dz

想問第10題的dy/dx要怎麼求？看得很亂@@

a+b+C > Yabc | 9. 若 a, b, c > 0,試證 3 10. 驗證 y = log(x + V1 +x)爲單調,從而求其反函數

求解第二題！ （因為圖片要兩題一起看所以順便拍進來了）

§ 1.1 An Intuitive Introduction to Limits For Exercises 1 and 2, use the graph of the function f to determine whether each statement is true or false. Explain.(從圖形決定極限) 1. O lim f(x)=XX/ x→-3+ lim f(x) = 1. x→2 2. a) lim f(x)=1. x-→-3+ e) lim f(x) does not exist. x →4+ c) lim f(x) = 2. x->2 b) lim x->0 flim f(x) = 3. x-5 d) lim f(x) = 3. x-4 f(x) = 2. Xe) lim f(x) does not exist. x →3 lim f(x) = 2. X→4 S b) lim f(x) = f(0). x->>0 d) lim f(x)=3. x->2* y 4 3 234 y = f(x)

求解釋這一題 看不太懂😭

例題:【反函數】 若f(x) = x²,f:[0,3]→[09],求 f(x)的反函數。 2: To9]→{0.3] 解: f(x) = x 在 [0,3]上為1-1 函數,取f'(x) = x,則有 f(f'(x)) = (√x)} = =x, ∀x∈[0,1] 345 S' (f(x))=√x² = =x,∀x∈[0,0],故f(x) 的反函數為」。 f(x)=xx 2:57/9:52 y X