-
Sidizzo son ei ji povaworl
grey line tolera
L
apapagoslingeri 14.0 V gool sign
S
qisning nanalintuniendizzo
00 6.00 (+
21.21.
Snus sur le mure on Roomet
while keeping it electrically the
4.0 2
es or parallel combinations of
918
b
+
a
oissant
10.0 V
sociated with combining resis-mollastunquodh (a)
emoved and replaced by a wire qoo
circuit.) Because the circuit is
his problem is one in which we
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6.02
100 9.00 (2 18.00
bus
M
2.0 2
abcda: (2) 10.0 V – (6.0 N) Į — (2.0 ₪) I₂ = 0
befcb: - (4.0 N) I2 − 14.0 V + (6.0 M) — 10.0 V = 0
-
1₂
Figure 21.21 (Example 21.4)
led in
branches.
moq
as labeled in Figure 21.21.mais12A circuit containing different
i svig 19 d
od oni bi u bliud
tot lo mo battib 210109 26919rw 1+ en slin
es
(1) 1₁ + 1₂2-1₂ = 01S sugit ni nobı aldı
YOU ARE
C
15usdwes
(2.02) 4₂2 01
Toyons de
=
L
d
(3) -24.0 V + (6.0 N) - (4.0 N)₂ = 0lvom snigul
grans di anioq gnilise or of am
gids de stod bad i
mi smo duo d
Monosh
10.0 V (6.02), − (2.0 N) (1,₁ + 1₂) = 0
Tom Tom
(4) 10.0 V - (8.02) 4₁
10 0
sob