工程與科技 大學 2年以上以前

1.30 plz用中文講解謝謝！

The message "Pass 0.12" is to be sent via communication line. For this, each character of the message should be encoded into a seven-bit ASCII code including the period and the it. Write the expression for the message sent. space. Each ASCII encoded character should be then encrypted by adding binary 101 to 1.29* Decode the following ASCII code: 10000110101110 1000010 1000001 1000010 1000010 1000010 1000111 1000101. 1.30 The following is a string of ASCII characters whose bit patterns have been converted into hexadecimal for compactness: 47 2E 5C 42 CF CF CC C5. Of the eight bits in each pair of digits, the leftmost is a parity bit. The remaining bits are the ASCII code. (a) Convert the string to bit form and decode the ASCII. (b) Determine the parity used: odd or even?

工程與科技 大學 3年以上以前

請問有沒有大神會翻成程式碼？ 我看不懂 Sieve algorithm

1.1 What Is an Algorithm? 33 for p 2 to n do A[p] - P for p < 2 to [n] do //see note before pseudocode if A[p]+0 llp hasn't been eliminated on previous passes jr p * P while j < n do A[j]0 //mark element as eliminated j<j+ p I/copy the remaining elements of A to array L of the primes if( 0 for p + 2 to n do if A[p] = 0 L[i] + A[p] iki +1 return L

工程與科技 大學 4年以上以前

計算機概論 請問第八題我這樣寫對嗎？ 快期末考了 想要allpass~

G Describe baSicS of programmed ]/O, interrupt-driven J/O, and DMA. (5 ptS) 呈池生 人 Desceribe the tundamentals of pipelining (5 pts) Deseribe the fundamentals of bootstrap process (5 pts) Using the instruction set and simple computer diagram, write the code for a program that performs(有九<一4+25+C+7) All values are acquired from the Keyboard and result is displayed on the monitor. Integer operation are assumed and overflow or negative number are not considered. The values in PC and 芭 for each cycle, and description for each instruction have to be included im he ansWwer. (10 pts)

工程與科技 大學 4年以上以前

Python 這樣為什麼錯？

輸入兩不同之整數 ,輸出 其大小比較 , 例如:輸入57,輸出5<7,輸出時不 要改變輸入值之順序,不必考慮兩整數 相同之情形。<或 > 前後皆有一隔空格 For example: Input | Result 彈 3<7 同 加 斧寢 天 ~-2 Answer: (penalty regime: 10, 20, ... %) 1 |a=num1 2 「b=num2 3yifa>b: 4|(a>b) 5yleUse 6 prlint (a <b)