請問箭頭指的算式誰能提供詳細的過程 怎麼求出0

輩終: 面及巔的積分 Ni gm 【例題2.14】對於半徑為? 之封閉型球面而言,證明 撬=0 g 解: # 向外之法向單位向量為避, 3 拓=- 1 呈 讓 Sin 9 豆 三sin 9cos伙十sin 9sin 交, 十cos 免. 信和 插=引二 呈 ,sin39cos%679+23 jsm 2sin 79 十互信 噴選 Sn 9cos 79=0 920 97

第五題求解

the percenta oltaege and (b) connectlion

Python 這樣為什麼錯？

輸入兩不同之整數 ,輸出 其大小比較 , 例如:輸入57,輸出5<7,輸出時不 要改變輸入值之順序,不必考慮兩整數 相同之情形。<或 > 前後皆有一隔空格 For example: Input | Result 彈 3<7 同 加 斧寢 天 ~-2 Answer: (penalty regime: 10, 20, ... %) 1 |a=num1 2 「b=num2 3yifa>b: 4|(a>b) 5yleUse 6 prlint (a <b)

答案為5.2乘10的6次方，求計算過程。

19 “Suppose that, while lying on abeach near the edquator watch- ing 了e Sun set over a calm ocean,you start a stopwatch Just as the top of the Sun disappears. You then stand, elevating your eyes by a height 五 三1.70 m, and stop 了he watch when the top of the Sun agaln disappears. 本 the elapsed time 18/ 三 11.1 s, what is the radius 7 OfEEarth? ae (0

求解~

補 Ch 上 人 國 4 芒 Ship between Earth an “品 0樣 im shape on the long interplanetary VOyages, 7了27y7je rotates EE to simulate Martian gravity. If the spacecraft s max1lmum diame Iun to cross the gap? teris 38.0 m, what should be its rotatlon period Me to comm 77ks, inhabits much of plete one rotation) if the acceleratlon at its outer edge 1s to equal 。 全 _m. A jumping mouse 人人 gravitational acceleratlon at Mars (see Appendix EE): Your car can Sustaln an ac- celeration of 0.795g while turning on adry road. You'YTe at minimum speed- zontaJy off the flat roofof Jower 插the gap between nce. (a) How fast and ecars the fence without distance coyered by a driving at 80.0 km/h when 五om height 五 you spot a truck jackknifed pround with the same across 訕e road. IF you swerve Tatlio of their flight inacircular arc, as shown in eu FIig. 3.25, how far from the truck do you have to start FIGURE 3.25 Problem Si 89 Amobi swerving to avoid the truck? W ydiree ume your speed doesn't change. With th 8./your alpine rescue team is using a slingshot to send an emer analoge gency medical packet to climbers stranded on a ledge, as Showt SMltuattot 本 FIg. 3.26; your job is to calculate the launceh Speed _ What 0 90 Yourm

請問的第6行為什麼不行呢

He 05.input用法- 0 X 人0 1091-993111a圭: xX「 @ rce/content/0/Ch4.練 M Gmail (自 CNUsers\小美XDesktop\0301.py - Sublime Text (U a=Yrnf(input()) File_Edit Selection_Find View Goto_Tools Project prefere 2人 b=39 1 主幾二 式設計| a< 199 and ,a<129: print(a+rb) a+b>129: print(arb*9.9) 國113人兀 服務費 司 Line6, Column 19

基礎C程式設計 拜託大家幫我 我想超久

Objective: 熟悉使用羅 算if else、for、while、do while 的用法 Exercise: 3.1 一個程式 數,若輸入不為正整數 接著判斷並輸 角形 屬於哪種三角形(種類:正三角形、等采三角形、 形) (註意 : 輸入的整數不會按大小排月 Input 1 Output 3.2 使用作業3. 1設計一個程式 使用for、do while、while,讓使用者可以 重複輸入10 而 起

想請問各位大大高手這題的詳解 非常的感恩

吧 是人|3 則 : 信 g F12-5 當 站 BR、ˋ質點以 Aa 0.2s) m/s? 的加速度沿直 線運動/ 式中。 的單位為公尺。若 s=0 時 o=5 s。試求 。=10倍 時質點的速度。 人 1 7人朱 -f( 凡人 症 人生和 ( 了 02 一 全 店/575 27 2 說 | | 說讓 - | F12-6 FI2-7, 買點以 g =(4/2-2)m/s? 的加速度沿直 運動。 式中直擊單位為秒。 如果 /=0 時質點在 踢!志側2 處、 ) 2s 時在原點左側 20 m 有虞

我看了答案還是不會算ಠ_ಠ

/97,/A ball is dropped from rest at a height 0o above the ground. At the same instant, a second ball 1s launched with speed uvo Stralght up from 崗e ground, at a point directly below where the other ball 1S dropped. (a) Find acondition on u0o Such that the two balls Will col- ide in mid-air. (b) Find an expression for the helght at Whieh they collde. 生 名 油1 ,

大一物理 救救我 還沒抓到解題技巧ಥ_ಥ

GBHINSWGW_SDSSUJID 0 Express 六還 m/s~. 0 km/h 2D) Sfarting 兩om rest, a Subway traln first accelerates to 25 mjJS at tis 並 也en brakes. Forty-eight seconds after Startlng, ltS moving % J8 m/s. What”s its average acceleration lin th1S 48-S lntervaly