為什麼第十題是用不定詞？

二、綜合測驗 (30%) 1 D 5 Awkwafina's talent goes beyond music. By 2014, she was appearing in TV shows regularly. She had even landed supporting _(8)__ in major films by 2018. These include Crazy Rich Asians and Ocean's 8. She was (9)__ in the latter without even auditioning! And in 2020, she became the first Asian American actress (10)__ a Golden Globe that award for Best Actress in a Musical or Comedy. She received it for her role in The Farewell, (1171 many of her lines were in Chinese. She learned it as a second language while studying in China. She also *ft Elt has a(n) _(12)__ for voice acting. She played the voice of Sisu the dragon in the movie Raya and the Last Dragon. She's also playing Ms. Tarantula in The Bad Guys later this year. 15.1 D DiAs@TA) leaps (C) layers 9. (A) cast (C) poured A (C) that win supporting roles 1A) 西乙 BOC) 10. (A) winning 11. (A) what won B) which --check IC C) 12. (A) extract (B) auditions (D) roles. (B) stirred (D) sliced (B) to win (D) who to win ( (D) in which (B) symbol (D) indicator DIB) 11. to the (C) that (C) talent

請問有人看得懂嗎😂

Genetics 普通生物學 UNIT THREE 觀念11: DNA定序(DNA Sequencing) 端 單股DNA和帶有放射性 1. Sanger法(Sanger method)或Sanger雙去氧鏈終止法(Sanger dideoxy chain termination method) : 1. 以5碳糖上第2和第3個碳均去氧的核苷酸為材料,合成的DNA之3', 不能再接新的核苷酸,造成DNA终止。 2. dsDNA加熱變性,快速冷卻成單股DNA, (PP)標示的primer 配對。 3. 反應時分成四管: a) #AZDNA+primer+DNA polymerase+4dNTPs+ddATP b) ADNA+primer+DNA polymerase+4dNTPs+ddTTP c) ADNA+primer+DNA polymerase+4dNTPs+ddGTP d) 單股DNA+primer+DNA polymerase+4dNTPs+ddCTP 4. 終止反應,並用聚丙醯凝膠(polyacrylamide gel) 電泳分離。 5. 顯影後判讀X光片即可讀出DNA序列。 6. Frederick Sanger 因為這個方法獲得1980年諾貝爾獎。 Primer 5 OH 3 3' -CTAAGCTCGACT Template dCTP, dGTP, DATP, DTTP + ddATP - GATTCGAGCTGddA GATTCGddA F GddA + ddCTP GATTCGAGddC GATTddC + ddGTP - GATTCGAGCTddG GATTCGAddG GATTCddG ddG + ddTTP - GATTCGAGCddT -GATddT - GAddT G 3' 12 11 10 G C uuu9876543 21 5 As Tcc AccTT AG Autoradiogram of electrophoresis gel Sequence of complementary strand 500 1610 T天就在 下一秒就看到,

想問18 19 20

III = n YouTube 109高一適性班_數學+ans .pdf el Google Keep 问 Notion - The all-in-one workspac X 17. 如下圖,在AABC 的兩邊AB 與 AC ,往外側作正五邊形ABDEF 及正五邊形ACGHT 則Z BOP = 度 图 D G B 9 109高一適性班數學+ans.pdf C Gx Google Translate N-'tiffany... 18. 如下圖所示,老師將同學排成7列,其中第2列的人數比第1列多2人,往後每一列的 人數都比它的前一列多2人。接著老師分別將210 顆標上成等差數列:3、10、17、24、,,, 的號碼球依序發給同學,由左而右先發完第1列的同學,再發第2列的同學 依此類推。已知老師發到第7列的最後一位同學剛好將210顆的號碼球發完,請問排在 第6列第17行的同學拿到的號碼球是幾號? X O 3 / 6 第第第 1 2 3 行行行 第1列(3 10 17 A Not secure | www2.tnssh.tn.edu.tw/department/academic/test/108下試題/高一適性班/109高一適性班數學+ans%20.pdf 24 7 WORD UP 第2列 e 34:21 min - Studying and Work " x 第3列 9 80% 第7列 0000 + G Google 0 9 19.一箱中裝有大小都相同的20個號碼球,編號由1號到20 號,今從箱中任意抽取一球 且每球被抽中的機會均等,並將所取到的號碼用來作為二次函數y = x + 3.x + k+1中的k 值。已知直線L的方程式為x+y-5=0,若小華從箱中任意抽取一球,則結果會使二次 函數的圖形與直線L不相交的機率為 O Toggl Track 5 Calendar || 想問13 15 - Clearnote ED D'S 20. 如圖,梯形ABCD,AD // BC,在 AD上取一點E,將A點 沿著 BE 對摺,使得A與重合;再將D點沿著 CE對摺,使 得D與D'重合,CD'與ATE 交於F點,且F在梯形ABCD的 內部。若ZATED' = 16", ZA FC = 60",ZBCF =40",則 ZAEB= 度 X > B + 0 英 Q g以 { 4 | . 1/6/2022 16:43 PM E Reading list ... D ... X

想問13 15

9 109高一適性班數學+ans .pdf 回 Notion-The all-in-one workspac X | X X 想問911 12 - Clearnote 0 32:47 min - Studying and Work X x|+ v | { C A Not secure | www2.tnssh.tn.edu.tw/department/academic/test/108下試題/高一適性班/109高一適性班數學+ans%20.pdf YouTube Google Keep 課程 Google Translate N-,tiffany... 7 WORD UP G Google 0 Toggl Track 5 Calendar 目 Reading list ||| 109高一適性班_數學+ans .pdf 216 100% + 14 . 上 F B D 13. 在坐標平面上,設二次函數y = 3x+2) +1的圖形為G, G對稱於x軸的圖形為G,, G. 對稱於軸的圖形為G,若圖形G, 所對應的二次函數為y= x' + bx +C,則實數序對 (a,b,c)=」 14. 用一條繩子緊緊圈住7個相等大小的圓,如右圖。若圓的半徑是2公分, 則圈住這7個等圓的繩長是多少公分? B 15. 如右圖,A ABC中,AB = BC, AD = BD, ZABC=90°。若O、G分別為A ABC的外心和 重心,且BC =2, DO 交 AG 於E,則EG O F G E 16. 右圖A ABC中,AB = 40, BC = 50, AC = 30 , 在RT 上的一里上),入ARD D要,但 9 英与 6:41 PM 1/6/2022

想問9 11 12

9 109高一適性班數學+ans .pdf 回 Notion-The all-in-one workspac X | X X | 想問135 - Clearnote 0 31:15 min - Studying and Work X x|+ v | { C A Not secure | www2.tnssh.tn.edu.tw/department/academic/test/108下試題/高一適性班/109高一適性班數學+ans%20.pdf YouTube Google Keep 課程 Google Translate Ñ 'tiffany'... 7 WORD UP G Google 0 Toggl Track 5 Calendar 目 Reading list ||| 109高一適性班_數學+ans .pdf 216 100% + . 1 y 9. Eitsfxy? – x² - y2 – 6xy +4 B(3,3) A(-2,0) D 0 10. 如圖,在直角坐標系中,4(-2,0)、B(3,3),D點為BC 與x 軸的交點,若AD平分∠BAC,且直線 AC 之方程式 為3x + my +k=0 其中m、k為實數),則m+k=. C 11. 花媽在某家時尚服飾店看上一件洋裝,於是使出她的殺價本領,要求老闆依定價打七折, 老闆說:「這樣我會賠 200元,即使依定價打八五折我也才賺25 元而已。」若老闆沒有 說謊,則這件洋裝的成本為多少元? 事 12. 如圖,在AABC中,AB:AC:BC=4:6:9,若AE =2, BF =1, CD=3,則 AACD 面積:ABAE 面積:ACBF 面積= A E F B D 量。」。 产, at - 9 英与 6:40 PM 1/6/2022

想問135

| X tiffany's Corne X | X 9 109高一適性班數學+ans .pdf 0 25:23 min Studying and Work x|+ A Not secure | www2.tnssh.tn.edu.tw/department/academic/test/108下試題高一適性班/109高一適性班數學+ans%20.pdf <> C YouTube Google Keep 課程 Google Translate tiffany'... 7 WORD UP G Google 0 Toggl Track 5 Calendar 目 Reading list III 109高一適性班_數學+ans .pdf 1/6 100% + . 填充題: (84%)每題4分 說明:請將答案依題號順序寫在答案卷上,否則不給分。 1. 已知將五個質數相乘後得到的積是一個六位數,且這六個阿拉伯數字皆相同,求此五個 質數的總和? 2. 若a=3.810 -3.8°,b=3.8'' -3.810,c= 1 = 3.8'' -3.8° 2 試比較a、b、c之大小關係? + 3. 已知多項式2x' -5.x + 2x=-35-84 可因式分解成(x + a)(x + b) (2.x + 3),其中a、b均 為整數,則a-b= - 4. 設4,12 (Gio 為等差數列,若(@ji + a)(as + ans) = (a + des) + 36,且 ass + as > 0,則此數列的總和為 9 10 88- 5. 伸出你的左手,從大拇指開始,如圖所示那樣數數字:1,2,3,…… 設u, 表第n次指到食指所數到之數字(例如:df = 2, as =8,ds = 10), ula49 = L ENG 6:34 PM 1/6/2022

21題 教教我QAQ

Section 11.3 Angular Momentum J-s behind rmv a he ur 265 = ? a ter 30. Example 11.1: A 58.1 Iw COMP string and whirled at 18. Express the units of angular momentum (a) using only the funda- momentum of magr mental units kilogram, meter, and second; (b) in a form involving the circular path. Fir newtons; (c) in a form involving joules. marw horizontal and (b) the 19. Use data from Appendix E to make an order-of-magnitude esti- 31. Example 11.2. A stai mate for the angular momentum of our Solar System about the Max 27 the end of its lifetime galactic center. mu = 17.293 of radius 4.96 X 10' 20. A gymnast of rotational inertia 63 kg•m? is tumbling head over heels dwarf of radius 4.21 with angular momentum 460 kg•m?/s. What's her angular speed? 17.99 acted on the core, fine A 660-g hoop 95 cm in diameter is rotating at 170 rpm about its 32. Example 11.2: Astro 22. A 1.3-th-diameter golf ball has mass 45 g and is spinning at central axis. What's its angular momentum? L: 1W=0-66*(0-95) x 140x277.10 km and determin core that collapsed to 3000 rpm. Treating the golf ball as a uniform solid sphere, what's ing with a period of 4 its angular momentum? 18-3 33. Example 11.2. The s 10-598 rpm With her arms outstre Section 11.4 Conservation of Angular Momentum tational inertia is 3.5 23. A potter's wheel with rotational inertia 6.20 kg•m? is spinning (Fig. 11.6b), her rot freely at 20.0 rpm. The potter drops a 2.50-kg lump of clay onto her final spin rate? L = 6 2 x 2-1 = 12-99~13 - 2x2 22 13= 60.48)" x 2.5 W W = 2 . X z W = 20x2T 60 ²2.1 ~ 1 12.574

第21題 到底要怎麼寫ಥ_ಥ

Section 11.3 Angular Momentum J-s behind rmv a he ur 265 = ? a ter 30. Example 11.1: A 58.1 Iw COMP string and whirled at 18. Express the units of angular momentum (a) using only the funda- momentum of magr mental units kilogram, meter, and second; (b) in a form involving the circular path. Fir newtons; (c) in a form involving joules. marw horizontal and (b) the 19. Use data from Appendix E to make an order-of-magnitude esti- 31. Example 11.2. A stai mate for the angular momentum of our Solar System about the Max 27 the end of its lifetime galactic center. mu = 17.293 of radius 4.96 X 10' 20. A gymnast of rotational inertia 63 kg•m? is tumbling head over heels dwarf of radius 4.21 with angular momentum 460 kg•m?/s. What's her angular speed? 17.99 acted on the core, fine A 660-g hoop 95 cm in diameter is rotating at 170 rpm about its 32. Example 11.2: Astro 22. A 1.3-th-diameter golf ball has mass 45 g and is spinning at central axis. What's its angular momentum? L: 1W=0-66*(0-95) x 140x277.10 km and determin core that collapsed to 3000 rpm. Treating the golf ball as a uniform solid sphere, what's ing with a period of 4 its angular momentum? 18-3 33. Example 11.2. The s 10-598 rpm With her arms outstre Section 11.4 Conservation of Angular Momentum tational inertia is 3.5 23. A potter's wheel with rotational inertia 6.20 kg•m? is spinning (Fig. 11.6b), her rot freely at 20.0 rpm. The potter drops a 2.50-kg lump of clay onto her final spin rate? L = 6 2 x 2-1 = 12-99~13 - 2x2 22 13= 60.48)" x 2.5 W W = 2 . X z W = 20x2T 60 ²2.1 ~ 1 12.574

求解a b c

4 The diagram below shows part of the graph of y = along with the point (2,0.5) on the graph. 15 (2.0.5) OS - .. The diagram also shows a rectangle with sides parallel to the axes, one vertex is the given point and the opposite vertex on the branch of the graph in the third quadrant (a) Find the position of the vertex in the third quadrant that gives the rectangle with the smallest possible area. (b) Calculate this smallest possible area. 121 (e) Suppose that a similar rectangle with opposite verices 1 (- :) -- ~ 5) where a > 0) and < 0) has the same area. Find a relationship between a and b. 141 Maximum mark: 11)

第17題應該要怎麼算

| 3-2) 1-5 馆 一 2722 125 立 麥卡1 投影 (D)14.哪兩種投影法中格陵蘭的面積最接近真實情況? (A)甲乙 (B)甲丁 (C)乙丙 D丙丁 (十) 15. 若要繪製各國使用 Instagram 的人口比例分布圖,最適合使用下列何種投影法? (AT (B)甲乙 (C)ZPJ D内工 (C)16. 在甲~丁四張圖中的粗線線段,何者並非大圓航線!? 距: 距離不足 (A) 甲 (B)乙 (C)丙 DT 大A夫婦參加蘇澳地區舉辦的半日生活節,拿到右方蘇 澳125.NER 的經建版地形圖進行活動,活動中有好幾個 關卡,各關也有關主進行解說,透過闖關活動可以讓參 加者更了解當地的發展脈絡。請問: S 5 D17. 大A拿到提示卡後,沿著臺九線從第一關蘇澳國 中前往第二關蘇澳海事職校,在不考慮任何自然 與人為因素耽誤的情況下,如果以步行時速5公 里/小時來計算,大A夫婦大約會花幾分鐘才能 抵達下一關? 334 335 ( (A) 6 (B) 12 ( (C) 23 (D 30 5 7 5 10.25 5 963 安國中, 斗法 三重 美泉 272 过国小 全世 336 337 0.2541) OS: 1.35% 30 359 (C)險 第三關蘇澳車站的關主出了一道超級難題,要回答出來才能拿到下一關的提示卡,題目是:「若以一 度緯度的經線長為110.7公里來計算,蘇澳車站的緯度最接近北緯幾度?」答案最可能為下列何者? (A) 22.8 (B) 23.5 (C) 24.6 (D) 25.1 50 (4) 19. 最後一張提示卡:「在最高的地方,迎來最後的禮物。」大A夫婦要前往的地方最可能位在何處 safizsoa 50 = = 12.5km 1 : 50 m ( (290.000 2,78 (A) (335350, 2721900) (B) (2721900 ,335330) (C) (2721800,336300) (D) (336300,2721800) 0 小瑜蒐集淡水河出海口與臺北港之地 甲 六塊厝漁港 質圖,如甲圖所示,若圖幅方格邊長 三芝區 IZ 乙 TES HEL2 于