這種題目怎麼算？

- cos150 + sín 240° + tan 60° - cos 60 十 % 23 A e(Q) C 已知 Pas a tailes 在第二象限內,則Qst a been 在第幾象限? -- (B) (D) (E)以上皆可能。 P 2 w

第八題的第5為什麼是對的

too cloist C 9 2 + 1 tot G D B 一) 7 右圖為一個稜長為1的正六面體,試問下列哪些選項是正確 的? WOÀ+OB+OC=0 TRAB AC=1 AB= (-;11) 11,0,1) (3) 40. BC=0 AL = H,O, (4) OC. BE=0 (5) I OB+OG | =1+2 itit 21 rotto) 10.10 E (1,00 | 了他 100 90 80 70 60 50 40 30 8. 右圖的散布圖中,每個點(X,Y)分別代表一位學生 於某次數學()與英文(Y)測驗成績。若數據中共有 11位學生,則下列哪些選項是正確的? (教 (1)若 60 分以上(含)為及格,則英文科的及格人數比 數學科多 (2) x #341762 >y 3 + 12 Yato pastabox f5** *2.70 (3)X的標準差>Y的標準差 久 (4) X的全距>Y的全距 X软集中 (GNY對X的最適直線的斜率小於-1 x的车<的起名 10 102030405060708090100 X 6kA & Lyra X中位数 数 9 -- 已知a=10^7,b=7/10,試問下列哪些選項是正確的? (已知log 2~0.3010,log 3~0.4771, log 70.8451,472.65, 10 >3.16 N450<< 500 (2) 450<b<500 (3)a> (整數部分是一個位數 (5) 10的整數部分其首位數字為3 = 2X0.4971 to. 6990+) log at 7 2 2,65 ac 450 (4) a" 033572-18 27 1986 1945 uslug9+ lugstluylo = + + gb= To log = 3.16 *0.845/= 2.670516 -2.6532 bakoo - 1045+ 2 21.5

想請問這題 謝謝🙏

( 1. 發多項式除以(x)的面式為Car),然式,則T(x)除以(2x+1), 一) 下列何者正確? (A)面式包(x),餘式R (B)面式 20 (x),餘式R (C面式 pasy 黛式及 C (D)面式 20 (x),餘式 2R (E)商式@g),歐式:

（平面向量） 請問這題的第四個選項要怎麼算？🙏 看了詳解後還是不清楚 謝謝

// 9 9 o past) , L y = x (x y o 0 SE Qlt.) 口) || 坐標平面上有相異兩點P,0,其中點坐標為(srt)。已知線段PQ 的中垂線L \"> (12) 的方程式為y=x,試問下列哪些選項是正確的? (NPO 與向量(1,1)平行 : -= (2)線段PQ的長度等於V2ls-t| ) SA-t- & (3)Q點坐標為(t,s) 2 y = stk (4)過0點與直線L平行之直線必過點(-s,-t) MC-5, -t) (5)以表示原點,則OP.PQ=00 - PO (4) Ma= (t.s)-(-3,-t) 過及且平了! =(tts, S+t)= (tts):(1.1) =) /過(-5, -t)#ANA-2-12 9 u、 (2,2, J2)

不知道b=-6是怎麼來的？

lo - 145 2 6143=64* 5. 已知b為實數且二次函數f(x) = x + bx + 2014,對於任意實數都有 Coos: 2.2 f(4+t) = f(2-t),則f(x-- 20103 一)之最小值為 E == 2014 EOT + (E- PIOS PIOS 41 7486 X 3 floq-f (6.)pos na pasta y = 2005 fox)=x²6X+2014 HHH HAX 2 =(x-3)²/2005 f(x - - (x-103 103 2014. 2014 - 3) +2005 el £ 2005 172a+b=41 24+6=27 zato29 229-29 la -

求解 謝謝

1+ 在坐標平面上有點4(3,-1) 及一圓C: x + y + 2x-4y=0。過點A作圓C的切線AP,其中 (x**115一4) (24)12-15) [ 點P為圓C上的切點。若點為圓C上任意一點。則向量內積 AP. AQ之最大值為30 APAO = AP x L Ão caso) o T107 全國聯模】 (1,2) W PASH TH A

第六題，怎麼算

6. Suppose that the targent line to the graph of a function f at x = 1 passes through the point (4,9) = and that f(1) = 3. Then f'(1) = 2 JJ斗笠 、恐日頭(60 分)

請問這題怎麼算出m.b

VE 14 r2 which passes through the point (1, (1) 4. The equation for the tangent line to the curve y = -1 3 is y = mx + b where m = and b 4 4 1 ( x2 if x < 2

想請問這題的正負該怎麼看🙏

25" ty- you 3, 3sinx - 2cosx,則當(cos x, sinx) = 生。 pas de trailing Discopyri) }) (1) 21 時,f(x)有最小值為 (1) 9-1 */ Vrg gilt 2- 9 ginx

求解第5題

PROPERTIES OF CURVES (Chapter 13) 340 ACTIVITY Click on the icon to run a card game on curve properties. REVIEW SET 13A b y = x - 5x + 2 at (2,0) 1 Find the equation of the tangent to: a y=-222 at the point where x = -1 1-2x at (1, - d f(x) = (3x-1 at the point where 1 = e f(x) = ln(x-2) at the point where x = e. 2 Find the equation of the normal to: a y = 13.1 +4 at (4,4) y = 3e2: a Find a. b at the point where I = 1. 3 At the point where x = 0, the tangent to f(x) = 4x + px + q has equation y = 50-1 Find p and q. 4 Find all points on the curve y = 22 + 3.22 - 10x +3 where the gradient of the tangent is 2 5 The line through A(2, 4) and B(0,8) is a tangent to y= (x + 2)2 6 Find where the tangent to y = 228 +4x – 1 at (1,5) meets the curve again. a Find the equation of the normal to y = e2c at the point where x = a. b Hence find the equation of the normal to y = e21 which passes through the origin. 8 Find the coordinates of P and Q if (PQ) 5 y = at (1,5). va 7 YA is the tangent to P (1,5) 5 y = Q The tangent to y = x+/T = c at * = -3 cuts the axes at points A and B. Determine the area of triangle OAB. Find intervals where f(x) = -23 - 6x2 + 36x - 17 is: a increasing Consider the function f(x) = 2x3 - 3x2 - 360 +7. a Find and classify all stationary points. b decreasing b Find intervals where the function is increasing and decreasing. Describe the behaviour of the function as 200 and as X-→ -0. d Sketch the graph of y=f(x) showing the