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設正方形ABCD的邊長為X 則CEFG邊長為(X-8)
邊長關係由畢氏定理可知AB²+BE²=AE²
⇒X²+(2X-8)²=20²
⇒5X²-32X-336=0
⇒(5X+28)(X-12)=0
⇒X=12 or -28/5(不合)
所以AB為12、CE為4、DG為12-4=8
DF為√8²+4²=4√5
答案為A
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