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TOEIC・英語 大学生・専門学校生・社会人

70の問題の回答がなぜDになるのかが分かりません。 因みにTOEICのリスニング問題のPart3です。

68. Who is the man? M It's such a pleasure to finally meet you, Olivia. As coordinator of this year's international trade conference, thank you for Transportation modes and how they can affect your supply chain"(B) An event coordinator accepting our invitation to lead one of our sessions. Saturday, November 19 10:00 am - 12:00 pm (A) An expert in international trade Sponsored by Dupree Logistics - Drew Flint, Senior Partner (C) A trade representative (D) An owner of an agency Room 101 W The pleasure is mine, Ruben. Our agency is always happy to have representatives 12:00 Noon - 1:15 pm 69. What has the woman agreed to do? (A) Lead a conference session (B) Conduct an interview (C) Schedule an appointment (D) Accept a new position Lunch participate in your conference. Witon Hotel - Wolfgang Puck's Spoon M As requested by your assistant, Jamie, your session has been scheduled for the afternoon of November 19. Ilf you check the schedule, you will see the title of your presentation listed in the last time slot on that day. 1:30 am - 3:00 pm 「Asia: A strategic approach to effectively developing and executing your Asian marketing plan" Sponsored by Blackbox Associates - Olivia Ingersol, Chief 70. Look at the graphic, Who does the woman Operating Officer Room 102 work for? 3:15 pm - 4:00 pm Closing Ceremony Wisconsin Center Ballroom (A) DuPree Logistics (B) The Witon Hotel (C) Wolfgang Puck's Spoon (D) Blackbox Assodiates W Thank you very much, and I'l see you at the conference.

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化学 大学生・専門学校生・社会人

熱力学について質問です。 問題文の一定の外圧1.00atmをどう扱ったら良いかよく分かりません。自分でとりあえず解いてみたんですが合ってる自信あまりないです。もし分かる方いらっしゃいましたら、ご教授していただけませんか?🙇‍♂️

Problem 2 A sample consisting of 1.00 mol of perfect gas molecules at 300 K is expanded isothermally from initial pressure of 3.00 atm of a final pressure of 1.00 atm against a constant external pressure of 1.00 atm. Determine the values of q, w, AU, AH, AS, ASsur, and AStotal. 300Kにある完全気体 1.00mol の試料が、 温度一定で始めの圧力 3.00 atm から終わりの圧 カ 1.00 atm まで、一定の外圧 1.00 atm に抗して、 膨張する。 この過程に対して、9, w, AU,AH, AS, AS r, ASiosal を求めよ。 管品可運勝張より、Tが喫化しないためるリ=D 始めの体様をV終わりの体殊をソュとおくと. V, = 8.314× 300 スH- AU + PAV 1660 [コ] 1660 8.21×(o°[m] AS = = 5.53 [h] 300 ニ 3×1, 013 × /D" Vz = 8.314x300 1.013× [0 外界が理た熱置はdisur = -AHよ) = 0.0276 [m] ASsur- 「desur T 1660 300-5.53[7h] Pdv = -1.013 x /0°x (0.0246- 8.21Y16') - こ M AStotal こ AS + ASU- = -1660 LJ] AV= 9+ W より 1 - -w- 1660[5] 0 Problem 3 Calculate the change in the molar entropy at 1 atm when a solid ethanol at 159 K of the melting point changes

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