Answers

∫∫e^-(x^2+y^2)dxdy
=∫∫e^(-x^2) e^(-y^2)dxdy
=∫e^(-x^2)dx ∫e^(-y^2)dy
=∫e^(-x^2)dx ∫e^(-x^2)dx
=(∫e^(-x^2)dx)^2

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