Question

妍

求解🙏🏻

10.
求2x²-17x++54x²-79x²+52x-12的一次因式
1=112
A. X=Worl
MSTC 2024
-2x-15x+15x²+390²-39x-4x+4x+2x-12
=2x+(x-1)-15x(x-1) +39x (x-1)-40x(x-1)-12 (x-1)
4-1672
-(2x-15x²+39x²-40x+12)(x-1) = (x-1x2x-1)(x-2) [x (2-2-319-2)]
=(x-1)(x-x14x²+7x²+3237-16x-4x+12)=(x-1) (2x-1)(x-2)(x-2)(3)
(x-1)(x(2x-12 1x (2x-1) + (6x(x-1)-1213x-1)) = (x-1)(2-1)(x-2)+(-3)
= (x-1) (2x-1)(x²-7x²-116x-12)
=
前提:因式分解
(x-(x2x-1)(x(x-2)-5(x-2)+6(x-2)
= (x1) (2x+17(x-2) (x²-5x+6) = (x-1) (2x-1)(x-2)(x²-2x-3x+6)
頁 2

Answer 1

✨ Jawaban Terbaik ✨

Ian

如圖

妍

看不太懂 可以說明一下嗎😓

Ian

ok, 打字不太好講解清楚

2x⁵-17x⁴+54x³-79x²+52x-12
帶入1, 2, 3,後可以等於0

代表2x⁵-17x⁴+54x³-79x²+52x-12包含(x-1)(x-2)(x-3)

利用長除法後剩下(x-2)(2x-1)

妍

很清楚！謝謝你☺️