✨ Jawaban Terbaik ✨
tanθ = sinθ/cosθ = 2
=> sinθ = 2cosθ
(sinθ)^2 + (cosθ)^2 = 1
=> (2cosθ)^2 + (cosθ)^2 = 1
=> 5(cosθ)^2 = 1
=> cosθ = -1/(5^0.5) (cosθ < 0)
sinθ = -2/(5^0.5)
2sinθ - 3cosθ = cosθ = -1/(5^0.5)
求過程
✨ Jawaban Terbaik ✨
tanθ = sinθ/cosθ = 2
=> sinθ = 2cosθ
(sinθ)^2 + (cosθ)^2 = 1
=> (2cosθ)^2 + (cosθ)^2 = 1
=> 5(cosθ)^2 = 1
=> cosθ = -1/(5^0.5) (cosθ < 0)
sinθ = -2/(5^0.5)
2sinθ - 3cosθ = cosθ = -1/(5^0.5)
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