Answers

diket : t1 = 0
t2 = 20
a1 = 0
a2 = -2
v0 = 5
ditanya : ∆EK?
dijawab :
* vt1 = v0 + at
= 5 + 0.0
= 5

* vt2 = v0 + at
= 5 + (-2).20
= 5 + (-40)
= -35

∆EK = ½m (v2² - v1²)
= ½.2 ((-35)² - 5²)
= (1.225 - 25)
= 1.200 J (e)

semoga membantu, semangat belajarnya🫶🏻

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