Question

佩

請問此題該如何解，謝謝

2.
試求lim
no
答:
1
√1x 2 + √√2 × 3+...+ √n(n+1)
n²
=
2
n²
2 ++
+ In(n+1)
n₂
n Jn (n+1)
n
lim
n(n+1)
Tim
n
③
282228221.0
EZE 2021222
1.0-2.212PP: 0-1

Answer 1

✨ Jawaban Terbaik ✨

imma_idiot

a < sqrt(a(a+1)) < a+1;
(n(n+1)/2)/n² < 原式 < ((n+1)(n+2)/2 -1)/n² ,
左右界皆為 1/2.