Question

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這是怎麼得到21.8的？我自己去查了反三角函數感覺我還缺一些前置基礎，所以希望可以有計算過程我之後自己研究

27 The diagram shows triangle ABP inside the regular hexagon ABCDEF
D
860² - 4
2
5
AB = 5 cm
Work out the size of angle PAF
Give your answer correct to 3 significant figures.
BP = 2 cm
E
Angle ABP = 90°
(6-2)-180 6/92=
120
=720
F
Diagram NOT
accurately drawn
X+3 6+4 = Do
x+y=90
442=120
*X-2=-

27
eg tan BAP = 2
5
2
√√5² +2²
5
√5² +2²
sin BAP =
cos BAP=
eg (BAP) tan
(BAP) sin
or
or
sin BAP
2
or cos BAP=
sin 90
√5² +2²
5²+(√5² +2²)²-2²
2x5x√√29
(= 21.8...) or
2
√√5² +2²
5
√√5² +2²
or (BAP) sin
(BAP =) cos
eg (int angle =) (6-2)x180÷6(=120)
or (ext angle =) 360+6(=60)
or BAP = cos™¹
eg "120"- "21.8" or 180- "60" - "21.8"
2 sin 90
√√5² +2²
5²+(√√5² +2²)²-2²
2x5x√√5² +2²
98.2
5
MI
MI for a complete method to find angle
BAP (= 21.8....)
[M2 for 90-tan
M1
M1
for setting up a trig equation for
angle BAP
A1
ie 90 - 68.2]
Indep for a method to find the size
of one interior or one exterior angle
in a regular hexagon - could be
seen on diagram
for a complete method to find angle
PAF where all values have come
from a correct method
accept 98.198.3
Total 5 marks

Answer 1

qn

按計算機

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我自己查過大概知道計算機怎麼按了不過我想說這樣沒有過程分