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✨ Jawaban Terbaik ✨

f(x) = (x-2)(x+1)q(x) + (2x-6)
f(0) = (-2)(1)q(0) + (-6) = 2
=> q(0) = -4
所以q(x)可以化成x(g(x)) -4
得f(x) = (x-2)(x+1)[x(g(x)) -4] + (2x-6)
= x(x-2)(x+1)g(x) -4(x-2)(x+1) + (2x-6)
故f(x)除以x(x-2)(x+1)的餘式為
-4(x-2)(x+1) + (2x-6) = -4*x^2 + 6x + 2

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