Question

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8、10求詳解嗚嗚嗚嗚

z (22-6)-0(x-3)
30 (x^)(x-3)
2-4+a(31)
(a+x+5)(30
_8.x{5} (x − 4)² + a(x −4) + 3(x-4) + 3a = [7₁-4) (a+*+h) tsag
(370)(x-4), (2-4)² + 30
(4) (+-12-4) (3x -1²) + α (2=4) +39
30%
9.3dx+by+ 3cx - ay-3bx-cy=
760-4) (0+1) 6-41 + ²2
³3 = catc-3b) y (b+a+C) 【 HELLI 】
3xCatc-by (btate)
_+0.5% 2ax − 8x+ 3by + 2bx+ 3ay-12y = (a+b) (27+ 3 4 ) ( 2 7 - ? ? ?
O
【文府】
= a (²x + 3√) 27 (4+6)-34 (46) ((+2234
福山】【道
q_
0

Answer 1

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