Question

㋛

這題要怎麼解🙏

(G.
3. 如圖,△ABC中,AD ⊥BC且AD=2,BD=1,若tan∠CAD
4%
NFC
155
2
B
1
D
+
NS
3
2
Htan BAC =
TOAD
2125
ENAT

Answer 1

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我就是我

tanBAD∠=1/2
tan∠BAC=tan(∠BAD+∠CAD)
=(1/2+3/2)/(1-1/2×3/2)
=4