Question

Fiona Tseng

求解 謝謝

10. 已知一線段 AB, AC = CD = DE = EB 。今以 B
點為圓心, BD 為半徑畫弧,再以 A 點為圓心, AE
,兩弧交於 F 點,連接 AF、EF、 BF,
如附圖所示。若 AB =28,則EF=0.5.
9) F
A
21
S
DE
14
A
C D
E
B

Answer 1

✨ Jawaban Terbaik ✨

Mer

過DG//BF
DG : BF = AD : AB = 1:2
DG = 7
△ADG與△FBE全等(SAS)
EF = AG = 21/2 = 10.5