Question

Uki

畫線處求解謝謝

【2】 設已知 ja₁x+b₁₂y=c₁
a₂x+b₂y=c₂
[(a₁ +2b₂₁)x+ (b₁-a₁)y = 3c₁
[(a₂ + 2b₂ ) x + (b₂ − a₂)y=3c₂
=
X = -2
x=y=12
22x+y=18
TH
=>
之解為(4,-6),試求下列方程組之解
a₁ ( X = ² ) + b₁ (²x + 3) = ²₁
3
1
y = -14
12/
+
11
【中和】
Ans: (-2,-14)
(a₁x+b₁y=c₁..