✨ Jawaban Terbaik ✨
Hitunglah kadar (% massa glukosa dalam larutan glukosa 4 molal (Mr glukosa=180)
Cara:
-massa glukosa = mol glukosa x Mr
= 4 x 180
= 720 gram
-massa larutan = massa glukosa + massa air
= 720 gram + 1.000 gram
= 1.720 gram
-massa glukosa = (massa glukosa/massa larutan) x 100%
= (720 / 1.720) x 100%
= 41,86%
Jadi, kadar (% massa glukosa dalam larutan glukosa 4 molal (Mr glukosa=180) adalah 41,86%