求解，謝謝🙏（大一物理）

A model rocket is launched straight upward. Its altitude y as a function of time is given by y = bt - ct², where b = 80 m/s, c = 4.9 m/s², t is the time in seconds, and y is in me- ters. (a) Use differentiation to find a general expression for the rock- et's velocity as a function of time. (b) When is the velocity zero?

（普物-光的折射） 請問這題要怎麼解 位置跟大小都需要解答 感謝🥲

EXAMPLE 34.11 An image of an image Converging lenses A and B, of focal lengths 8.0 cm and 6.0 cm, respectively, are placed 36.0 cm apart. Both lenses have the same optic axis. An object 8.0 cm high is placed 12.0 cm to the left of lens A. Find the position, size, and orientation of the image produced by the lenses in combination. F₁ 2 Lens A 12.0 cm 8.08.0 cm cm F2 -24.0 cm- 36.0 cm FL 3' 2' 3. 1' Lens B 3,1% 2' -3' F₂ 12.0 cm*12.0 cm K6.0><6.0 cm cm I' 23

請問第26題⋯ 我的計算機無法計算三次方根 但由答案回推又不正確 想請問我的式子是否有誤？

3 48= 3a a Jr (2)4.42g/cm (C) Sodium crystallizes in a body-centered cubic structure (as drawn here) with a density of 0.97g/cm². Estimate its atomic radius. (A) 95pm (B)320pm (C)370pm (D) 190pm. p=0191= (brige)x a a 1.903x10 a² = 2.903x10? (108台大A) "in a face centered cubic lattice. The density of (D) - ha 3 Go 6x102 Q3 cm 27. Tunntal mare only miato 11izen in

請問第44題要怎麼寫? 第二張圖是我的寫法，因為cu->cu2+發生氧化反應，所以另一個的氧化E°必須小於cu的,這樣cu才能發生氧化，請問這種想法是錯的嗎?? :(

44. Which one of the following reagents is capable of transforming Cu(s) to Cuf* (1 M)? A) I (1M) B) Ni(s) C) Ag" (1 M) D) AP* (1 M) E) Hf (1 M) Ans: C Category: Medium Section: 19.3 45. Which one of the following reagents is capable of transforming Fe3+ (1 M) to Fe2+ (1 M)?

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Compound semiconductors can be doped to make n-type and p-type materials, but the scientist has to make sure that the proper atoms are substituted. For example, if Ge were doped into GaAs, Ge could substitute for Ga, making an n-type semi- conductor; but if Ge substituted for As, the material would be p-type. Suggest a way to dope CdSe to create a p-type material.

想請問這題微分過程

*/ 8 司 HTTP ox 十 0 OPT lx. Isothermal compressibility Expansion coefficient 人.…等), p = =() - Prove that )+ ( o ) pe (4)) -洋),()+ (r) ( 学) = =(等);(学) - -(-) t () p (3 (部) () = ", 。 | 8²v POT 'T ; &T V ²v Stop 可上 T 宁 0 &

請問這個詳細的數學過程改如何解呢？😆

ob 1so. NTT A2 sin² x) ex dx = 1 oba une List NTT or sinal 1 noituloa - on sing on to augi od Isseyda od mol 02(x) dx 4²= eniging Jotem je JO.21 sun -di es el I xorg Ispieyda olmam: 1 svim -x dx = 2 os noies Joil L ojos I SMO The value of the integral is L/2, which means that Or X 0.5 = cilidio boos 1 vllando A = n/2 dong L - 1 = 210 A² 1 101 V Lixdo noir . 42 . 2 =

請各位幫我解釋一下第15題🙏🙏

1-5 理想氣體方程式 39 -B612 PV - 4XT - V. I Vi : V2 = 2/3 + 4 三、非選擇題 y14 右圖所示為某 定量的 理想氣體之P-T圖(壓力-溫度圖) 原來 為狀態A,其體積為V,經某過程後成為狀態B,其體積為V2, 见力(P) 0 45° 53 离度(T) 57 cm Hg 注意圖中夾角的度數,則V 與V, 的比值為 中 2 15 圖一所示,一玻璃管長 57 cm,管底封閉,在25°C、latm 下裝滿氮氣後,鉛直倒壓入一水銀槽內,直到管底與水銀槽的 [line 水銀面等高,如圖所示。若外界之壓力及溫度不變,則此時 管內之氮氣壓力應為1.5 atm . 16.51A = 96th) ha h 38 cm 16 試回答下列密閉定容氣體實驗:P-16+ / 11 ord : = 1.5 atm (1)如右圖所示,在20°C、latm下做實驗,未加熱時,p、q兩 水銀面等高,將p高度固定,加熱至50°C時,q比p高出7.6 cm,若繼續加熱,當p、q高度差為19 cm時,燒瓶中氣體的 19cm 溫度為 °C。 (2)此時燒瓶中氣體的壓力為 活塞 17. 如右圖所示,可自由滑動之活塞兩端分別放入4atm之He 及1atm 在等下達平衡時,活塞將右 玻璃管 玻璃管 燒瓶 水 p 水 軟橡皮管 atm. o X He 0

34🙇‍♀️🙇‍♀️🙇‍♀️

34 ConsIider elements with the atomic numbers listed below. Assuming tbe atotns were neufral which of和了em would be least chemlically reactlve? A)

大一普化 5.36求解

5.38 9389 信4 5,42 sphere (about 30 Where the temperatu lbove the surface of Earth), >and presSure are 一235C : h gd 交 and 3.00 XX 10 atm, respectively. Calculate the final Volume of the balloon. The temperature ot 2.5 L of a gas initially at SUN increased to 2507”C at constant volume. Calculate the final pressure of the gas in atm. The pressure of 6.0 L of an ideal gas in aflexible contalner 1S decreased to one-third of its original presSure, and 1ts absolute temperature 1s decreased by one-half. What 1s the flnal volume of the gas? A gas evolved during the tfermentation of glucose (wine making) has a volume of 0.78 L when mea- sured at 20.1?C and 1.00 atm. What was the volume of this gas at the fermentation temperature of 36.5 C and 1.00 atm presSure? An ideal gas originally at 0.85 atm and 66”C was allowed to expand until its final Volume, preSSure, and temperature were 94 mL, 0.60 atm, and 45 C, respectively. What was its initial volume? The volume of a gas at STP is 488 mL. Calculate 1ts volume at 22.5 atm and 1507C. A gas at 772 mmHg and 35.0”C Qceuples a Volume of 6.85工. Calculate its volume at STEP. Dry ice is solid carbon dioxide. A 0.050-g sample ot dry ice js placed in an evacuated 4.6-L vessel at 30。C. Caleulate the pressure inside the VesSel after all the dry ice has been conVerted to CO gasS, Avolume of 0.280Lofagas at STP weighs 0.400 g. Calculate the molar mass Of the gas. Aquantity of gas Weighing 7.10g at741tor and 445C oeeupies a volume of 5.40L. What is its molar mass? Si人2 5.93 5.54 Dalt 和Ae0U76 5 5.56