解答

10.
假設邊長 a
(a+3)^2 = 4a^2
a^2 +6a +9 = 4a^2
3a^2 -6a -9 =
a^2 -2a -3 = 0
(a-3)(a+1) = 0
a = 3 or -1(不合)

11.
等腰 => x^2 - 3 = x + 9
x^2 -x -12 = 0
(x -4)(x +3) = 0
x = 4 or -3(不合) => 兩股長 = 4 + 9 = 13 => 斜邊長 = 13√2

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