Question

嘟嘟靜

設f(x)表定義域為正整數的函數 且f(1)=999 又對n ≥2的任意整數n 恆有f(1)+f(2)+f(3)+...+f(n)=n^2f(n)
求f(999)=

Answer 1

✨ 最佳解答 ✨

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Call me Bravo

We can find a pattern f(n)=(1/((n+1)/2)(n))f(1)=>f(n)=(2/(n+1)(n))f(1), so f(999) as up picture.