Question

🐶

求解

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已知x+x-5=0,則(x+2)(x+4)x-1)(N-3)的值為
AJ?
(X+2)(x+4)(x-1) (3)
raa
A) – 24 =>(X+4X+2x+8)(x-DLX-3
- 24
X)
(B) – 21
(X x 768-6x +8X-8)x-2)
(C) – 18
Lü 704 +5X? +2X-8)(x-3)
(D) – 14 => y* - 3y + 53 - 158 +3X-14X+24
x 3 2x²
330

Answer 1

Mer

(x+2)(x-1)(x+4)(x-3)
=(x²+x-2)(x²+x-12)