Question

sarah

請解釋感謝

I:
6. 已知二次函数f(x)滿足條件(2-1) = f(-4+1),其中1為任意實數,且
f(2)-f(3) = 14 , f(-5)-f(-4)=
-14
469- 360150310172
fl-4)= 25ath
Sfath) - (15th
ella
f(x) = a (x+)²th
f(2)= atb
f(3) = 40th
Cath-140th)
f(5)-f(-4)= f(3)-f(2)= -[f(2)=f03) 1- 1430 14
並序軸上的箭園。

Answer 1

LY02

f(-5)=f(-4-1)=f(2-(-1))=f(3)
f(-4)=f(-4-0)=f(2-0)=f(2)

Answer 2

LY02

［(2-t)+(-4+t)］/2=-1
f(x)=a(x+1)^2+b