Question

squidy._.

拜託了🥺

6.
設數列{an)為一個等差數列,且 aio + a11 = =,試求 201 x202 x203 x…x2020 之值。
zaior d = 3
(25g

Answer 1

✨ 最佳解答 ✨

我就是我

a10+a11=2a1+19d=3/5
(2^a1)(2^a2)(2^a3)...(2^a20)
=2^(a1+a2+a3...+a20)
=2^(20a1+190d)
=2^(20a1+190d)
=2^(3/5*10)
=64